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notsponge [240]

3 years ago

15

In the diagram, point D divides line segment AB in the ratio of 5:3. If line segment AC is vertical and line segment CD is horiz

ontal, what are the coordinates of point C?

2 answers:

quester [9]3 years ago

7 0

The answer is B. (2,-1)

Vesna [10]3 years ago

6 0

Answer:

Step-by-step explanation:

(Plato) - Answer D: (2, -1)

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Consider circle A in the diagram below

Artyom0805 [142]

<h3>Answer: Choice D) 56 degrees</h3>

How I got that answer:

Angle DCE is given to be 62 degrees. By the inscribed angle theorem, It doubles to 124 degrees, which is the measure of central angle DAE.

Note how angles DAF and DAE are a linear pair. This means they are adjacent supplementary angles. So they add to 180

(angle DAF)+(angle DAE) = 180

(angle DAF) + (124) = 180

angle DAF = 180-124

angle DAF = 56

5 0

3 years ago

Read 2 more answers

What are the solutions of 4x^2 -8x+5=0

Ilia_Sergeevich [38]

Answer:

It is no real solutions

Step-by-step explanation:

5 0

2 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

2 years ago

Please help me if you can thank you. For question A the answer is 5000 brochures. My question is how did they get that answer?

Sophie [7]

Answer:

Step-by-step explanation:

Company A's equation is 900+0.50x5,000

Company B's equation is 1,500+0.38x5,000

Both equal 3,400 and have to be multiplied by 5,000

8 0

2 years ago

What is the simplified form of i ^32?<br> A. -i<br> B. 1<br> C. i <br> D. -1

ElenaW [278]

divide exponent by 4

since the remainder is zero, the equation can be rewritten as i^0 and any number to the 0 power is 1

5 0

3 years ago

Read 2 more answers