Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
JL = 78
Step-by-step explanation:
The shorter segment is a midline, so is half the length of the longer one.
2(5x-16) = 4x +34
5x -16 = 2x +17 . . . . . divide by 2
3x = 33 . . . . . . . . . . add 16-2x
x = 11 . . . . . . . . . . divide by 3
Then segment JL is ...
JL = 4x +34 = 4(11) +34 = 44+34
JL = 78
