C hope it helps .....................
The Given equation is , 3 x + x = 440,
Let speed of train A is x Km/hour and Speed of train B which is a Bullet train which starts from same station but from different platform is 3 times the speed of train A.
And Sum of their Velocities is i.e Velocity of train A and Velocity of train B is 440 Km/hour.
X=105°
Y=105°
Z=105°
let the angle below 75° which is the 4th Street be A
75°+A=180°[being adjacent angle]
A=105°
X=A[Verticall opposite angle]
Z=A[Corresponding angle]
Y=X[alternate angle]
2arctan(2/5) = 44°
180° -44° = 136°
The angles are 44°, 136°.
10y^2 - 23y + 12 = 10y^2 - 15y - 8y + 12 = 5y(2y - 3) - 4(2y - 3) = (5y - 4)(2y - 3)
