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mel-nik [20]
3 years ago
11

Which expression is equivalent to -4(7-2m)+11m

Mathematics
1 answer:
dimulka [17.4K]3 years ago
8 0

Answer:b

Step-by-step explanation:

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the first one is true:)

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Which of the following is an example of the Associative Property?
photoshop1234 [79]
(13 + 20) + 15 = 13 + (20 + 15)
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3 years ago
If AE=6x-55 and EC=3x-16, find DB. (Hint: Find x first and then substitute.)
erica [24]

<u>Given</u>:

Given that ABCD is a rectangle.

The diagonals of the rectangle are AC and DB.

The length of AE is (6x -55)

The length of EC is (3x - 16)

We need to determine the length of the diagonal DB.

<u>Value of x:</u>

The value of x can be determined by equating AE and EC

Thus, we have;

AE=EC

Substituting the values, we get;

6x-55=3x-16

3x-55=-16

       3x=39

         x=13

Thus, the value of x is 13.

<u>Length of AC:</u>

Length of AE = 6(13)-55=78-55=23

Length of EC = 3(13)-16=39-16=23

Thus, the length of AC can be determined by adding the lengths of AE and EC.

Thus, we have;

AC=AE+EC

AC=23+23

AC=46

Thus, the length of AC is 46.

<u>Length of DB:</u>

Since, the diagonals AC and DB are perpendicular to each other, then their lengths are congruent.

Hence, we have;

AC=DB

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Thus, the length of DB is 46.

6 0
3 years ago
The sum of three numbers is 8. The third is 9
Ierofanga [76]

Answer:

→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>

→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>

→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>

Step-by-step explanation:

• let numbers be x, y and z

{ \tt{z = 8y - 9 -  -  - (eqn \: 1)}} \\  \\ { \tt{10x = 8y - 7 -  -  - (eqn \: 2)}} \\  \\ { \tt{x + y + z = 8 -  -  - (eqn \: 3)}}

• from eqn 2, make x the subject:

{ \tt{x =  \frac{8y - 7}{10} }} \\

• substitute all variables in eqn 3:

{ \tt{ \frac{8y - 7}{10}  + y + 8y - 9 = 8}} \\  \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\  \\ { \tt{98y = 177}} \\  \\ { \boxed{ \tt{ \: y = 1.8}}}

• find z

{ \tt{z = 8y - 9}} \\  \\ { \tt{z = 8(1.8) - 9}} \\  \\ { \tt{z = 14.4 - 9}} \\  \\ { \boxed{ \tt{ \: z = 5.4 \: }}}

• find x:

{ \tt{x =  \frac{8(1.8) - 7}{10} }} \\  \\ { \tt{x =  \frac{7.4}{10} }} \\  \\ { \boxed{ \tt{ \: x = 0.74 \: }}}

Rounding to nearest value:

{ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{  \rm{z = 5}}}

7 0
3 years ago
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