3 years ago

How would I solve for h?

Mathematics

1 answer:

alexandr1967 [171]3 years ago

7 0

You have to get h by itself first

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Express the following rate as a unit rate. If necessary, round your answer to the nearest tenth. 63 quarts for 56 seconds

gavmur [86]

Answer:

1.1 qt/s

Step-by-step explanation:

To find quarts per second, divide quarts by seconds:

(63 qt)/(56 s) = 9/8 qt/s ≈ 1.1 qt/s

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2 years ago

Drag the blue point to a place on the number line

sergejj [24]

Answer:

The number line is shown below.

Step-by-step explanation:

We need to represent number that is less than 3 on a number line.

Let x be numbers.

So, $x$ .

Now, we have a number which represents x<3. Here 3 is not included in the solution set, so there is an open circle on 3 and left side of 3 are in the solution set.

The number line is shown below.

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3 years ago

What is 289% as a decimal

lakkis [162]

Answer:

the answer is 2.89

Step-by-step explanation:

u divide 289 to 100 or 289/100=2.89

hope this helps

4 0

2 years ago

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The numbers on the line plot

densk [106]

The picture isn't very clear

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3 years ago

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

4 0

3 years ago