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AnnZ [28]
3 years ago
6

How many quarts of soil are used to fill 2 flower pots?

Mathematics
1 answer:
Anna35 [415]3 years ago
5 0

Answer:

25 (3/5)

Step-by-step explanation:

i did this on a test lol

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What is the equation of the graphed line written in
frutty [35]

Answer:

Step-by-step explanation:7

8 0
3 years ago
The sum of two numbers is 72 the greater number is 8 more than the smaller number which equation can be used to solve for the sm
kobusy [5.1K]

Answer:

let x is the smaller number

bigger number is x + 8

The sum of two numbers is 72

so

x + (x+8) = 72

answer

x + (x + 8) = 72

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
4(x+1.5)=38 solve for x
Kitty [74]

Answer:

x = 8

Step-by-step explanation:

4(x+1.5)=38

Distribute the 4

4x +6 = 38

Subtract 6 from each side

4x+6-6 = 38-6

4x = 32

Divide each side by 4

4x/4 = 32/4

x = 8

3 0
4 years ago
A video game store allows customers to rent games for $4.75 each. Customers can also buy a membership for $54 each year, and vid
Nezavi [6.7K]

Answer:

24

Step-by-step explanation:

Cost of membership + game = 2.50x + 54

Cost of just games = 4.75x

The catch is, how do we make up the 54 dollars?

So equate the 2 costs

4.75x = 2.50x + 54      Subtract 2.50

4.75x - 2.50x = 54       Combine

2.25x = 54                    Divide by 2.25

x = 54/2.25

x = 24

That means that 24 is the break even point.

5 0
4 years ago
PRECALCULUS<br> Please look at every picture and answer all questions, thanks.
Marta_Voda [28]
1. so it has to have every x is one y and every y has one x
graph them
we see that the only ones that are one to one are the first one, the 2nd one and the 4th one

2.
solve for x and replace with f⁻¹(x) and y with x
minus 8 and cube both sides
(y-8)³=x-2
add 2
(y-8)³+2=x
replace
f⁻¹(x)=(x-8)³+2
first one


3.
this is a one to one function because theer is no vertical line that could intersect the graph more than once
ah, I see, you're program has a different one to one definition, no horizontal or vertical line can cross, lemme edit te first question again
answer is 2nd option


4. a neat trick is this:
the domain of f(x) is the range of f⁻¹(x)
the range of f(x) is the domain of f⁻¹(x)

the domain of f(x)=1/(3x+2)
hmm, can't divide by 0 so set denomenator to 0
3x+2=0
3x=-2
x=-2/3
domain is all real numbers except -2/3
(-infinity,-2/3)U(-2/3,infinity)
that's the range of f⁻¹(x)

range
ok, hmm, range is from positive initny to 0 then from 0 to positive inifnty, not including 0

so the domain of f⁻¹(x) is (-∞,0)U(0,∞)
range of f⁻¹(x) is (-∞,-2/3)U(-2/3,∞)
first option
8 0
3 years ago
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