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Tom [10]
3 years ago
10

Consider the following sequence

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
6 0

Answer:

Solution given:

first term [a]=152

second term[b]=-76

common ratio[r]=\frac{-76}{152}=-1/2

now

for nth term ,we have

nth term =a {r}^{n -1}

now

7th term==152{-1/2}^{7 - 1}

=152×1/64=19/8

wlad13 [49]3 years ago
3 0

Answer:

a₇ =  2.375

Step-by-step explanation:

There is a common ratio r between consecutive terms, that is

r = \frac{-76}{152} = \frac{38}{-76} = \frac{-19}{38} = - \frac{1}{2}

This indicates the sequence is geometric with nth term

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 152 and r = - \frac{1}{2} , then

a_{n} = 152 (-\frac{1}{2}) ^{n-1} , so

a₇ = 152 (-\frac{1}{2}) ^{6} = 152 × \frac{1}{64} = 2.375

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