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3 years ago

Write the ratio! Cos/Sin/Tan!

Mathematics

1 answer:

Hatshy [7]3 years ago

4 0

Answer:

Step-by-step explanation:

sin A= 21/29

cos A=20/29

tan A=21/20

sin B =20/29

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* Review - Interpreting the Remainder*

Likurg_2 [28]

She will need 9 computers. She has 8 groups of 3 and 1 group of 2. Therefore, she will need 9.

6 0

2 years ago

What is -2 and 2 fifths squared?<br><br> Thanks!

Luba_88 [7]

Answer:

$\frac{144}{25}$

Step-by-step explanation:

We begin with $(-2 \frac{2}{5} )^2$

First, lets turn this mixed number into an improper fraction/

$-2 \frac{2}{5} =-\frac{12}{5}$

Now that we have this, we can square it and then simplify it.

$(-\frac{12}{5} )^2 =\frac{12^2}{5^2} *(-1)^2=\frac{144}{25} *1=\frac{144}{25}$

3 0

3 years ago

What is the equation of the tangent line passing through the point (0, 3) of the graph of the function f(x) = x2 − 2x + 3?

Sergeeva-Olga [200]

Answer:

y = -2x + 3

Step-by-step explanation:

The given equation is:

$f(x)=x^2-2x+3$

First we need to find the slope of the tangent line. This can be done by finding the derivative of the given function.

$f'(x)=2x-2$

Slope of the tangent will be the value of the derivative at the given point. So the slope of tangent is:

$f'(0)=2(0)-2=-2$

Now we have slope of the tangent line and a point (0, 3) on the tangent. The point (0,3) is the y-intercept of the tangent line. So we can use slope-intercept form to directly write the equation of the line.

The slope intercept form of an equation is:

y = mx + c

where m is the slope and c is the y-intercept.

Using the values: m = -2 and c = 3, we get:

y = -2x + 3

This equation represents the tangent line

8 0

4 years ago

If f(x)=2^x-1 and g(x)= x^2-1, determine the value of (f o g)(3)

zimovet [89]

Answer: 4

Step-by-step explanation:

( f o g ) (3) means f(g(3)) so...

First: plug 3 into g(x) = x^ (2-1)

3^ (2-1) is 3^1 = 3

Next: plug 3 into f(x)= 2^(x-1)

2^(3-1) is 2^(2) > 2×2 = 4

3 0

3 years ago

Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)

Drupady [299]

Answer:

The equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

Let us solve the expression step by step to get the equivalent

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

$\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=x^{2\cdot \frac{1}{7}}$

$=x^{\frac{2}{7}}$

also

$\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=y^{3\cdot \frac{1}{5}}$

$=y^{\frac{3}{5}}$

so the expression becomes

$\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$ ∵ $\:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}$

Thus, the equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

5 0

3 years ago