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tresset_1 [31]
3 years ago
11

An automobile assembly line operation has a scheduled mean completion time, , of minutes. The standard deviation of completion t

imes is minutes. It is claimed that, under new management, the mean completion time has decreased. To test this claim, a random sample of completion times under new management was taken. The sample had a mean of minutes. Assume that the population is normally distributed. Can we support, at the level of significance, the claim that the mean completion time has decreased under new management
Mathematics
1 answer:
lidiya [134]3 years ago
7 0

Answer:

Step-by-step explanation:

Here are the missing values;

Mean μ = 15.5 minutes

Standard deviation = 1.7 minutes

A Random sample of 90 completion

The sample mean = 15.4 minutes

Level of significance = 0.1

Then the following analysis can be made on the above study.

Firstly, the null hypothesis is \mathbf{H_o : \mu = 15.5}

the alternative hypothesis is \mathbf{H_a: \mu < 15.5}  

Since, the value is less than, then this is a one-tailed test.

The Z test statistics can be computed as:

Z = \dfrac{ \overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}  }  \ \  \sim  \ \  N(0.1)

Z = \dfrac{ 15.4-15.5 }{\dfrac{1.7}{\sqrt{90}}  }

Z = \dfrac{ -0.1 }{\dfrac{1.7}{ 9.4868}  }

Z = −0.560

The critical value of Z at 0.1  level  of significance is:

Z_{0.1} = -1.28

Decision Rule: We fail to reject the null hypothesis sInce -0.560 > -1.28

Conclusion: NO, there is no evidence to support the claim that the mean completion time has decreased. We conclude that the mean completion time remains at 15.5 minutes.

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4 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

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b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

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c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

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