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algol [13]
4 years ago
11

A set of equations is given below: Equation A: u = 4v + 1 Equation B: u = 3v + 5 Which of the following is a step that can be us

ed to find the solution to the set of equations?

Mathematics
1 answer:
ss7ja [257]4 years ago
4 0
I am not sure if this answers your question exactly, but because both equations are equal to "u" than you can equal them to each other. 

It would be the last answer because you are setting them equal to each other.

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Add or Subtract.<br> 7/24 - 5/36
lisov135 [29]

Answer:

A product of a number and 12 is increased by 23

8 0
1 year ago
Which is a true answer
Ivanshal [37]

Answer:

F. 1.978 > 18979

Step-by-step explanation:

8 0
3 years ago
A gardener has 640 feet of fencing to fence in a rectangular garden. One side of the garden is bordered by a river and so it doe
kari74 [83]

9514 1404 393

Answer:

  • 160 ft (out from the river)
  • 320 ft (parallel to the river)

Step-by-step explanation:

Let x represent the length of fence parallel to the river. Then the dimension of perpendicular to the river will be half the remaining fence: (640-x)/2. The total area will be ...

  A = x(640-x)/2

This is the equation of a parabola that opens downward. It has zeros at x=0 and x=640, so its axis of symmetry is x = (0+640)/2 = 320. That is, the peak of the area curve is found when x=320.

The dimensions of the garden with the largest area are 160 ft wide by 320 ft long, where the long side is the river side.

6 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
4 years ago
Read 2 more answers
What is the value of the discriminant for the quadratic equation 0=2x^2+x-3? discriminant = b^2-4ac
sasho [114]
The discriminant is : (1)^2 + (-4)*(-3)*(2) = 1+24 = 25
3 0
3 years ago
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