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3 years ago

The sum of five consecutive multiples of 4 is 20.Find the smallest integer.

Mathematics

1 answer:

Aloiza [94]3 years ago

6 0

Answer:

The smallest integer is -4.

Step-by-step explanation:

Let the smallest integer be x.

Since the integers are all multiples of 4, they are

=> x, x+4, x+8, x+12 and x+16

=> x + x+4 + x+8 + x+12 + x+16 = 20

=> 5x + 40 = 20

Subtract 40 from both sides of the equation

5x +40 - 40 = 20 - 40

5x = -20

Divide both sides by the coefficient of x(which is 5)

$\frac{5x}{5} = \frac{-20}{5}$

x = -4

∴ the smallest integer is -4.

Hope this helps!!!

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3 years ago

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Pepsi [2]

Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of $m$ and the second line has a slope of $\frac{1}{-m}$ .

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We now know that $m = \frac{5}{2}$ for the first line, which means that the slope of the second line is $m = \frac{-2}{5}$ . With this, we have the following equation for our new line:

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where $C$ is the Y-intercept that we now need to determine with the coordinates given in the problem statement, $(5, -4)$ :

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