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Jet001 [13]
3 years ago
5

The sum of five consecutive multiples of 4 is 20.Find the smallest integer.

Mathematics
1 answer:
Aloiza [94]3 years ago
6 0

Answer:

The smallest integer is -4.

Step-by-step explanation:

Let the smallest integer be x.

Since the integers are all multiples of 4, they are

=> x, x+4, x+8, x+12 and x+16

=> x + x+4 + x+8 + x+12 + x+16 = 20

=> 5x + 40 = 20

Subtract 40 from both sides of the equation

5x +40 - 40 = 20 - 40

5x = -20

Divide both sides by the coefficient of x(which is 5)

\frac{5x}{5} = \frac{-20}{5}

x = -4

∴ the smallest integer is -4.

Hope this helps!!!

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anzhelika [568]

Well we know that...a^{-1}=\frac{1}{a^{1} }\\.

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Read 2 more answers
Solve the following equations for x<br><br> 13−(2x+2)=2(x+2)+3x
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