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Alona [7]
3 years ago
9

Find the perimeter of the triangle to the nearest unit A(-2,3) B(2,1) C(-2,1)​

Mathematics
1 answer:
siniylev [52]3 years ago
7 0

Answer:

  10 units

Step-by-step explanation:

We can find the length of the hypotenuse of this right triangle using the Pythagorean theorem.

  AB² = AC² +BC²

  AB² = 2² +4² = 20

  AB = √20 ≈ 4.47

Then the perimeter is ...

  P = AB +BC +CA = 4.47 +4 +2 = 10.47

  P ≈ 10 units

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Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
How to change 0.225 into a fraction
Aloiza [94]
I believe it’s 9/30
8 0
3 years ago
Two brothers, Gethin and David, share a sum of money in the ratio 2:7.
Vitek1552 [10]

12£ and 42£

Step-by-step explanation:

gethin gets 2/9

David gets 7/9

total money is equal to 54

Gethin gets 54x 2/9=12

David gets 54x7/9=42

4 0
3 years ago
A rectangular prism has a volume of 60 cubic centimeters. The height of the prism is 3 centimeters. What is the area of the base
Step2247 [10]

Answer:

Area = 20 square centimeters

Step-by-step explanation:

V = lwh

V = lw3

V = 4x5x3

V = 60

A = lw

A = 4x5

A = 20

5 0
3 years ago
What value of k makes the statement true?<br> x² (2x³ + 7x²yª) = 2xªyª + 7x³y8?
Nina [5.8K]

By apply the distributive property of multiplication, the value of k which makes the statement true is 1.

<h3>What is the distribution property?</h3>

Mathematically, the distributive property of multiplication is given by tis expression:

x(y + z) = xy + xz.

Next, we would apply the distributive property of multiplication to the given equation by distributing to the left-hand side using xy⁴:

k(2x⁴y⁴ + 7x³y⁸) = 2x⁴y⁴ + 7x³y⁸

Dividing both sides by the common factor, we have:

k = (2x⁴y⁴ + 7x³y⁸)/(2x⁴y⁴ + 7x³y⁸)

k = 1.

In conclusion, the value of k which makes the statement true is 1.

Read more on distributive property here; brainly.com/question/2807928

#SPJ1

<u>Complete Question:</u>

What value of k makes the statement true?

x^ky⁴(2x³ + 7x²y⁴) = 2x⁴y⁴ + 7x³y⁸

5 0
2 years ago
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