Origin = (0,0)
To find the units of distance subtract the given pair from origin
(0,4) - (0,0) = 4
The product of A and B matrix will be option D; BA = ![\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2610%2639%5C%5C-32%26-30%26-18%5C%5C-6%26-6%26-19%5Cend%7Barray%7D%5Cright%5D)
.
<h3>What is the multiplication of matrix?</h3>
If ![A = \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
and ![B = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D)
then,
BA = ![\left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right] \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
BA =
Hence, the product of A and B matrix will be option D; BA = .
Learn more about matrix here;
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Answer: 23,550,000 .......
Answer:
The answer is t=1/9
Step-by-step explanation:
If we substitute sqrt(t) = u, then we can write the equation as 3u^2+5u-2=0.
Using the <em>quadratic formula</em>, we can solve that <u>u = 1/3 and u = -2.</u>
We can go back to our original substitution and say that <em>sqrt(t) = 1/3</em>. The sqrt(t) can not be -2 because a <u>square root can not be negative.</u>
If we solve the equation sqrt(t) = 1/3, we get that t=1/9.
Answer:
6
Step-by-step explanation:
Substitute 1/4 with 8a. 8/4=2
Next, Substitute 10 for 0.5. 10/2=5
Finally, find the sum
(2-1)+5
6
