Answer:
x2 - 10x - 1994
Step-by-step explanation:
Step 1 :
Trying to factor by splitting the middle term
1.1 Factoring x2-10x-1994
The first term is, x2 its coefficient is 1 .
The middle term is, -10x its coefficient is -10 .
The last term, "the constant", is -1994
Step-1 : Multiply the coefficient of the first term by the constant 1 • -1994 = -1994
Step-2 : Find two factors of -1994 whose sum equals the coefficient of the middle term, which is -10 .
-1994 + 1 = -1993
-997 + 2 = -995
-2 + 997 = 995
-1 + 1994 = 1993
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
x2 - 10x - 1994
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Answer:
10.8 kg
Step-by-step explanation:
w = 80 + 5.4t
At time 0, when he starts the diet, his initial weight is
w = 80 + 5.4(0)
w = 80
80 kg.
After 2 months, t = 2. His weight is
w = 80 + 5.4t
w = 80 + 5.4(2)
w = 80 + 10.8
w = 90.8
90.8 kg.
His gain in 2 months was 90.8 kg - 80 kg = 10.8 kg
Answer: 10.8 kg
Answer:
59-60 F and 15 C
Step-by-step explanation:
Hope this helps!
A brainlist would be appreciated! I'm almost an expert!
You did it right (almost, I got 21 instead of 19) but didn't finish. You need to show your discriminant is never negative.
x² + (p+1)x = 5-2p
x² + (p+1)x +(2p-5) =0
Real roots mean a positive (or at least non-negative) discriminant:
D = b² - 4ac = (p+1)² - 4(1)(2p - 5) = p² + 2p + 1 - 8p + 20
D = p² - 6p + 21
It's not totally obvious that D>0; we prove that by completing the square by noting
(p-3)² = p² - 6p + 9
so
p² - 6p = (p-3)² - 9.
D = p² - 6p + 21
D = (p-3)² - 9 + 21
D = (p-3)² + 12
Now we clearly see D>0 always because the squared term can't be negative, so D is always at least 12. We always get two distinct real roots.
