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2 years ago

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At a summer camp, 5 out of 12 campers are signed up for horseback riding. If there are 432 campers at the camp, how many are sig

ned up for horseback riding?

1 answer:

beks73 [17]2 years ago

4 0

Answer:

The answer is 180.

Step-by-step explanation:

(5/12) x 432 = 180

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If f(x + 2) = 6x2 + 5x − 8. Find f(6).

Blababa [14]

Answer:

108

Step-by-step explanation:

We can rewrite f(x+2) to make it easier to evaluate:

f(x+2) = (6x +5)x -8

Since we want f(6), we want x+2 = 6, or x=4.

f(6) = (6·4 +5)·4 -8 = 29·4 -8

f(6) = 108

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3 years ago

On the shelves of Maria's bookcase,1/2 of the books are mysteries,1/10 are science fiction, 1/5 are biographies,and the remainin

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There are 12 books in her bookcase

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3 years ago

What is the value of this expression 6 7/8+ 4 1/5+ 8 1/2

S_A_V [24]

Answer:

Fraction:783/40 Decimal:19.575

Mixed:19 23/40

Step-by-step explanation:

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3 years ago

In a city of 64,000 people, there are 20,000 people under 25 years of age. What percent of the population is under 25 years of a

tatiyna

31.25% of the population is under 25 years of age. To figure this out, divide 20,000 by 64,000. Then, multiply that answer by 100 to get a percentage. Hope this helps!!

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3 years ago

If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.

zmey [24]

Answer:

$a=3$ and $b=5$ .

Step-by-step explanation:

So I believe the problem is this:

$\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}$

where we are asked to find values for $a$ and $b$ such that the equation holds for any $x$ in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

$\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)$

$2(4x+3)=a(x+7)+b(x-3)$

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

$2(4\cdot -7+3)=a(-7+7)+b(-7-3)$

$2(-28+3)=a(0)+b(-10)$

$2(-25)=0-10b$

$-50=-10b$

Divide both sides by -10:

$\frac{-50}{-10}=b$

$5=b$

Now we have:

$2(4x+3)=a(x+7)+b(x-3)$ with $b=5$

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

$2(4\cdot 3+3)=a(3+7)+b(3-3)$

$2(12+3)=a(10)+b(0)$

$2(15)=10a+0$

$30=10a$

Divide both sides by 10:

$\frac{30}{10}=a$

$3=a$

So $a=3$ and $b=5$ .

4 0

3 years ago

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