Question

A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of the circle. What is the ratio of the area of the square to the area of the circle?

Answer 1

r=AB=AC=BC, AD=r/2, ED=DF=CD=squareroot(3.r)/2

The area of square is : (EF)^2=(squareroot(3.r))^2=3r^3

The area of circle is : (pi.r^2)

The ratio will be: 3/pi