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ss7ja [257]
3 years ago
11

A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase

by 5% each year for the next 10 years and wants to reduce the amount of money spent on supplies by 2% for each student each year. Use the drop-down menus to choose or create functions to model:
A. The predicted number of students over time, ()
()=
B. The predicted amount spent per student over time, ()
()=
C. The predicted total expense for supplies each year over time, ()
()= () ___ ()
Mathematics
1 answer:
34kurt3 years ago
4 0

Step-by-step explanation:

The predicted number of students over time, S(t)

Rate of increment is 5% per year.  

A function 'S(t)' which gives the number of students in school after 't' years.  

S(0) means the initial year when the number of students is 200.

S(0) = 200  

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.  

S(1) = 200 + 5% of 200 = = =  

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)  

S(2) = S(1) + 5% of S(1) = = =  

.  

.  

.  

.  

.  

Similarly  

The predicted amount spent per student over time, A(t)

Rate of decrements is 2% per year.  

A function 'A(t)' which gives the amount spend on each student in school after 't' years.  

A(0) means the initial year when the number of students is 40.  

A(0) = 40  

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.  

A(1) = 40 + 2% of 40 = = =  

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)  

A(2) = A(1) + 2% of A(1) = = =  

.  

.  

.  

.  

.  

Similarly  

The predicted total expense for supplies each year over time, E(t)

Total expense = (number of students) ×  (amount spend on each student)

E(t) = S(t) × A(t)

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

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\left(6x10^2\right)\div \left(3x10^{-5}\right)
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Answer:

\frac{6\times 10^2}{3\times 10^{-5}} = 2 x 10⁷

Step-by-step explanation:

Given expression is \frac{6\times 10^2}{3\times 10^{-5}}

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3 years ago
A basketball player makes a free throw 82.6% of the time. The player attempts 5 free throws. Use a histogram of the binomial dis
DiKsa [7]

Answer:

The most likely outcome is exactly 4 free throws

Step-by-step explanation:

Given

n = 5 --- attempts

p = 82.6\% ---- probability of a successful free throw

p = 0.826

Required

A histogram to show the most likely outcome

From the question, we understand that the distribution is binomial.

This is represented as:

P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}

For x = 0 to 5, where x represents the number of free throws; we have:

P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}

P(X = 0) = ^5C_0 * 0.826^0 * (1 - 0.826)^{5-0}

P(X = 0) = ^5C_0 * 0.826^0 * (0.174)^{5}

P(X = 0) = 1 * 1 * 0.000159 \approx 0.0002

P(X = 1) = ^5C_1 * 0.826^1 * (1 - 0.826)^{5-1}

P(X = 1) = ^5C_1 * 0.826^1 * (0.174)^4

P(X = 1) = 5 * 0.826 * 0.000917 \approx 0.0038

P(X = 2) = ^5C_2 * 0.826^2 * (1 - 0.826)^{5-2}

P(X = 2) = ^5C_2 * 0.826^2 * (0.174)^{3}

P(X = 2) = 10 * 0.682 * 0.005268 \approx 0.0359

P(X = 3) = ^5C_3 * 0.826^3 * (1 - 0.826)^{5-3}

P(X = 3) = ^5C_3 * 0.826^3 * (0.174)^2

P(X = 3) = 10 * 0.5636 * 0.030276 \approx 0.1706

P(X = 4) = ^5C_4 * 0.826^4 * (1 - 0.826)^{5-4}

P(X = 4) = 5 * 0.826^4 * (0.174)^1

P(X = 4) = 5 * 0.4655 * 0.174 \approx 0.4050

P(X = 5) = ^5C_5 * 0.826^5 * (1 - 0.826)^{5-5}\\

P(X = 5) = ^5C_5 * 0.826^5 * (0.174)^0

P(X = 5) = 1 * 0.3845 * 1 \approx 0.3845

From the above computations, we have:

P(X = 0)  \approx 0.0002

P(X = 1) \approx 0.0038

P(X = 2)  \approx 0.0359

P(X = 3)  \approx 0.1706

P(X = 4)  \approx 0.4050

P(X = 5) \approx 0.3845

See attachment for histogram

<em>From the histogram, we can see that the most likely outcome is at: x = 4</em>

<em>Because it has the longest vertical bar (0.4050 or 40.5%)</em>

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Answer:

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Step-by-step explanation:

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