Answer:
Claim is true that most medical malpractice lawsuits are dropped or dismissed.
Step-by-step explanation:
Given :In a study of 799 randomly selected medical malpractice lawsuits, it was found that 499 of them were dropped or dismissed.
To Find : Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed.
Solution:
n = 799
x = 499
We will use one sample proportion test

We are given that the claim is most medical malpractice lawsuits are dropped or dismissed.
Probability of dropped or dismissed is 1/2

Formula of test statistic = 
=
= 7.038
p value (z>7.038) is 0
α =0.05
So, p value < α
So, we reject the null hypothesis
So,claim is true
Hence most medical malpractice lawsuits are dropped or dismissed.
Answer is C. 52 hours. because you divide the amount her earned with the $24 that he gets each hour
Answer:
distributive property
Step-by-step explanation:
(3x + 7) + (2x + 8)
each of the parenthesis has a multiplier of 1 , placed outside the parenthesis.
then multiplying the terms inside the parenthesis by 1 gives
3x + 7 + 2x + 8
Answer:



[since in third quadrant cos 30=-![\frac{\sqrt{3}}{2}]](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5D)

:150°or 
<u>150°</u><u>or</u><u> </u>
<u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer: 192.75
Step-by-step explanation:
I am answering your question assuming that the three amounts were checks that were written out during the week.
Beginning balance = 345.28
Subtract the total amount of the checks (65.08 + 24.50 + 118.95 = 208.53)
345.28 - 208.53 = 136.75
Next, add the amount of the deposit. 136.75 + 56.00 = 192.75