Answer:
a) 0.06
b) 0.778
Step-by-step explanation:
Let's suppose a community of 100 families just to facilitate the calculation.
30% of the families own a dog
Dog = 30% of 100 = 30
20% of the families that own a dog also own a cat = 20% of 30 = 6
27% of all the families own a cat = 27% of 100 = 27
So, 6 families own a dog and a cat.
As 30 families own a dog, [30 - 6 =] 24 families own only dogs
As 27 families own a cat, [27 - 6 = ] 21 families own only cats
See picture attached.
a) What is the probability that a randomly selected family owns both a dog and a cat?
P(dog and cat) = dog ∩ cat/total = 6/100 = 0.06
b) What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
So, only cat/total cat
P (not dog|cat) = 21/27 = 0.778
Answer:
Solution A = 2100
Solution B = 700
Step-by-step explanation:
Given that:
Let :
Millimeter of solution A = a
Millimeter of solution B = b
% alcohol, solution A =. 20% = 0.2
% alcohol solution B, = 14% = 0.14
Resulting millimeter of. Alcohol = 518
a = 3b - - - (1)
0.2a + 0.14b = 518 - - - - (2)
Put a = 3b in (2)
0.2(3b) + 0.14b = 518
0.6b + 0.14b = 518
0.74b = 518
b = 518 / 0.74
b = 700
a = 3b
a = 3(700)
a = 2100
Answer:
25 Is 25/100 And Means That It Is 25 %
◊ YusuCr ◊
Answer:
Search it up on goodle.
Step-by-step explanation:Its on goodle i thing
