7 , 14 , 21 , 28 __ __ _

Anyone can help me with math for solving for a side in the right triangles for khan academy

Elden [556K]

Answer:

7.45

Step-by-step explanation:

We are given a right triangle with one side length known and an angle know so we can use some trigonometry.

You need to find the hypotenuse so you are going to use either sine or cosine.

Since the adjacent from the angle is given (SOH-CAH-TOA) we can use cosine so,

cos(20) = 7/h

=>h = 7/cos(20)

=> 7.44924

=> 7.45

6 0

2 years ago

(Please answer before 5:15 P.M tonight)

taurus [48]

The scale factor of dilation from ABC to $A^{1} B^{1} C^{1}$ is 0.333.

Step-by-step explanation:

Step 1:

First, we plot the coordinates of both triangles.

The coordinates of the triangle $A^{1} B^{1} C^{1}$ are as follows;

$A^{1}$ = (2, 3), $B^{1}$ = (2, 1), and $C^{1}$ = (3, 1).

The coordinates of triangle ABC are;

A = (4, 9), B = (4, 3), and C = (7, 3).

Step 2;

Next, we need to find the distances between at least two coordinates for both triangles.

The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.

The distance of $A^{1} B^{1} = 3-1=2$ , the distance of $B^{1} C^{1} = 3-2=1$ .

The distance of AB $=9-3=6,$ the distance of BC $= 7-4=3.$

Step 3;

To calculate the scale factor, we divide the measurement after scaling by the same measurement before scaling.

In this case, it is the length of the AB.

So The scale factor for AB = $\frac{2}{6} = \frac{1}{3} = 0.333.$

The scale factor for BC = $\frac{1}{3} = 0.333.$

7 0

3 years ago

If a rectangle has a base of 6 units, and a height of 8 units, what is its area?

Morgarella [4.7K]

Answer:

a=48 units^2

Step-by-step explanation:

The area of a rectangle can be found using:

a=bh

We know the base is 6, and the height is 8, so we can substitute them in

a=6*8

a=48

Area uses units squared, so,

a=48 units^2

4 0

3 years ago

Read 2 more answers

Calvin is building a fence. The fence will enclose a 100 square foot area, 10 ft wide by 10 ft long. Calvin can put fence posts

Mashutka [201]

Answer:

20 fence posts.

Step-by-step explanation:

Calvin is building a fence. The fence will enclose a 100 square foot area, 10 ft wide by 10 ft long. Calvin can put fence posts 2 feet apart.

Now, if he puts a fence post at each corner of the building, then considering each length of the building there will be $(\frac{10}{2} + 1) = 6$ posts along each length.

Now, considering each width of the building there will be $(\frac{10}{2} - 1) = 4$ posts (excluding the corner posts) along each width.

Therefore, in total there will be (6 + 6 + 4 + 4) = 20 fence post in the total fence. (Answer)

5 0

3 years ago

the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width

-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

$\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}$

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

$\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}$

On solving the above expression for x we get

$\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}$

$\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}$

Hence length and width of rectangle is 15 inches and 6 inches.

4 0

3 years ago

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