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pogonyaev
3 years ago
6

To test the durability of cell phone screens, phones are dropped from a height of 1 meter until they break. A random sample of 4

0 phones was selected from each of two manufacturers. The phones in the samples were dropped until the screens broke. The difference in the mean number of drops was recorded and used to construct the 90 percent confidence interval (0.46,1.82)
to estimate the population difference in means.

Consider the sampling procedure taking place repeatedly. Each time samples are selected, the phones are dropped and the statistics are used to construct a 90 percent confidence interval for the difference in means. Which of the following statements is a correct interpretation of the interval?
Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

See below.

Step-by-step explanation:

I see there are no answer choices you've provided, but in order to interpret a confidence interval correctly, you might say something like "We are 90% confident that the true difference in the mean number of drops is contained within the interval".

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M or the slope has to be constant throughout the graph. This is because in order for a line to be linear it has to be increasing or decreasing at the same rate. So it the slope was 2 from point x 1 -2 then the slope changed to 1 from 3-4 it would not be linear. :)

7 0
3 years ago
Round this number to nearest 10,000. 4,278,003
s2008m [1.1K]

Hi there!

To Round of the number given, first you have to find the ten thousands place on the given number. Started from ones, tens, hundreds, and moving on, the number in the ten thousands place would be 7 in your case.

Now, looking to the number on the right of 7 which is 8, it is bigger than 5, and therefore, we round up 7 and let 8 go to zero.

Applying this, your answer would be 4,280,003

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Sedaia [141]

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Step-by-step explanation:


7 0
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Juli2301 [7.4K]

Answer:

Step-by-step explanation:

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Answer:

\large\boxed{\dfrac{3(6)-1}{2(6)+1}}

Step-by-step explanation:

\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\text{We have}\\\\f(x)=3x-1,\ g(x)=2x+1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{3x-1}{2x+1}\\\\\left(\dfrac{f}{g}\right)(6)\to\text{put x = 6 to the equation of the function}\ \left(\dfrac{f}{g}\right)(x):\\\\\left(\dfrac{f}{g}\right)(6)=\dfrac{3(6)-1}{2(6)+1}

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3 years ago
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