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pogonyaev
3 years ago
6

To test the durability of cell phone screens, phones are dropped from a height of 1 meter until they break. A random sample of 4

0 phones was selected from each of two manufacturers. The phones in the samples were dropped until the screens broke. The difference in the mean number of drops was recorded and used to construct the 90 percent confidence interval (0.46,1.82)
to estimate the population difference in means.

Consider the sampling procedure taking place repeatedly. Each time samples are selected, the phones are dropped and the statistics are used to construct a 90 percent confidence interval for the difference in means. Which of the following statements is a correct interpretation of the interval?
Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

See below.

Step-by-step explanation:

I see there are no answer choices you've provided, but in order to interpret a confidence interval correctly, you might say something like "We are 90% confident that the true difference in the mean number of drops is contained within the interval".

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Graph a line that contains the point (4, 3) and has a slope of 1/2
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Answer:

y=1/2x+1

Step-by-step explanation:

one dot on the 1 on the y axis

then more one unit up and two units to the left

and then from the first point (0,1) go one unit down

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What are the steps to converting 720 seconds into hours?
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A ladybug's length is 2cm. Measure it in meters. And Explain your thinking.
trasher [3.6K]

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We intend to estimate the average break time of Dunder Mifflin employees. From a previous study, we believe that the average tim
arsen [322]

Answer:

The minimum sample size that we should consider is of 60 employees.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

We want our 99 percent confidence interval to have a margin of error of no more than plus or minus 2 minutes. What is the smallest sample size that we should consider?

We need to find n for which M = 2, \sigma = 6

So

M = z*\frac{\sigma}{\sqrt{n}}

2 = 2.575*\frac{6}{\sqrt{n}}

2\sqrt{n} = 2.575*6

Simplifying by 2

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n = 59.67

Rounding up

The minimum sample size that we should consider is of 60 employees.

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