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3 years ago

Part B

Mathematics

1 answer:

lianna [129]3 years ago

6 0

Answer:

Soccer: 19 Males

Basketball: 29 females

Total: 40 males, 60 females

Step-by-step explanation:

MALES FEMALES TOTAL

SOCCER ║ 19 ║ 31 ║ 50 ║

BASKETBALL║ 21 ║ 29 ║ 50 ║

TOTAL ║ 40 ║ 60 ║ 100 ║

[OPTIONS ⇒ 19, 29, 40, 60]

SOCCER:

x + 31 = 50

50 − 31 = 19

19 males

BASKETBALL

21 + y = 50

50 − 21 = 29

29 females

TOTAL:

F: 31 + 29 = 60

M: 19 + 21 = 40

60 + 40 = 100

60 females

40 males

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Multiply. What is the value of the second partial product? 26 × 107

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Answer:

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Step-by-step explanation:

(20*100)+(20*7)+(100*6)+(7*6)

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3 years ago

Find the value of y possible answers are: A. y=1.8 B. y=7.2 C. y=9 D. y=16.2

Dahasolnce [82]

Answer:

I believe the answer is C.

Step-by-step explanation:

I put in 9 into the y

6(9)= 54

4(9)+18=

36+18= 54

Add them with the right angles (which are 90)

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3 years ago

If you invest $100,000 in an account earning 8% interest compounded annually, how long will it take until the account holds $300

Monica [59]

We have been given that you invest $100,000 in an account earning 8% interest compounded annually. We are asked to find the time it will take the amount to reach $300,000.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$8\%=\frac{8}{100}=0.08$

$300,000=100,000(1+\frac{0.08}{1})^{1\cdot t}$

$300,000=100,000(1.08)^{t}$

$\frac{300,000}{100,000}=\frac{100,000(1.08)^{t}}{100,000}$

$3=(1.08)^{t}$

$(1.08)^{t}=3$

Let us take natural log on both sides of equation.

$\text{ln}((1.08)^{t})=\text{ln}(3)$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$t\cdot \text{ln}(1.08)=\text{ln}(3)$

$\frac{t\cdot \text{ln}(1.08)}{\text{ln}(1.08)}=\frac{\text{ln}(3)}{\text{ln}(1.08)}$

$t=\frac{1.0986122886681097}{0.0769610411361283}$

$t=14.274914586$

Upon rounding to nearest tenth of year, we will get:

$t\approx 14.3$

Therefore, it will take approximately 14.3 years until the account holds $300,000.

7 0

3 years ago

Listed below are amounts of strontium-90 (in millibecquerels, or mBq) in a simple random sample of baby teeth obtained from r

Alenkinab [10]

Answer:

The 5-number summary is maximum= 175, minimum=126, median=150, Q₁=138 and Q₃=160.5.

Step-by-step explanation:

The given data set is

126, 128, 131, 135, 136, 140, 143, 145, 147, 148, 152, 154, 155, 156, 159, 162, 164, 166, 169, 175

The minimum value of the data is 126 and the maximum value of the data is 175.

Divide the data in two equal parts.

(126, 128, 131, 135, 136, 140, 143, 145, 147, 148), (152, 154, 155, 156, 159, 162, 164, 166, 169, 175)

The median of the data is

$Median=\frac{148+152}{2}=150$

Now divide each parenthesis in two equal parts.

(126, 128, 131, 135, 136), (140, 143, 145, 147, 148), (152, 154, 155, 156, 159), (162, 164, 166, 169, 175)

$Q_1=\frac{136+140}{2}=138$

$Q_3=\frac{159+162}{2}=160.5$

Therefore the 5-number summary is maximum= 175, minimum=126, median=150, Q₁=138 and Q₃=160.5.

8 0

4 years ago

I need help its homwork!!

pashok25 [27]

Th e answer to this question is is combining like terms on both sides

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3 years ago