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2 years ago

Six men take five days to complete a job. How long would the same job take fifteen men?

Mathematics

1 answer:

Bond [772]2 years ago

6 0

Answer:

2 days

Step-by-step explanation:

Understanding :

Number of men is inversely proportional to the number of days taken to complete a job
6 men take 5 days to complete 1
Now the number of men is 15

Solving :

Rate of change of men ∝ 1/Rate of change of days
15/6 ∝ 1/(d/5)
2.5 = 5/d
d = 2 days

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In the song "Rap God," Eminem can spit

vampirchik [111]

Answer:

200

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Leo bought 50 lbs of clay for his art projects. He used 12.5 lbs to make a sculpture, and 0.72 lbs for each mug. How many mugs d

ExtremeBDS [4]

Answer:

Total number of mug = 14 mugs

Step-by-step explanation:

Given:

Total amount of Clay Leo bought = 50 lbs

Total amount of Clay left = 27.42 lbs

Total amount of Clay used in sculpture = 12.5 lbs

Amount of clay each muh need = 0.72 lbs

Find;

Total number of mug

Computation:

Assume;

Total number of mug = a

So,

Total amount of Clay Leo bought = Total amount of Clay left + Total amount of Clay used in sculpture + (Amount of clay each muh need)(Amount of clay each muh need)

50 = 27.42 + 12.5 + (0.72)(a)

50 = 39.92 + (0.72)(a)

(0.72)(a) = 10.08

a = 14

Total number of mug = 14 mugs

8 0

3 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$