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Gwar [14]
2 years ago
8

The hypotenuse of a 30 -60 -90 triangle is 13cm. What is the length of the shorter leg?

Mathematics
1 answer:
Ivahew [28]2 years ago
6 0

Answer:

(13/2) cm

Step-by-step explanation:

The hypotenuse here is of length 13 cm.  The shorter leg lies opposite to the 30° angle.  Recall that the sine function is defined as

              opposite side

sin Ф = -----------------------

                 hypotenuse

which, in this case, works out to:

                opposite side

sin 30° = -----------------------

                       13 cm

and so the length of the opposite side (which is also the "shorter leg") is

shorter leg length = (13 cm)(sin 30°) = (13 cm)(1/2) = (13/2) cm

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A square table top has an area of 36 cm sq . What is each side?
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6 because 6 times 6 is 36
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Consider the sets A = fa; b; c; ; ; ; 1; 2; 3g, B = f ; ; ; ; ; g , C = f1; 2; 3; 4; 5; 6g and D = fa; b; cg. (a) List the eleme
Ilya [14]

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Step-by-step explanation:

4 0
3 years ago
A storage shed is to be built in the shape of a box with a square base. It is to have a volume of 686 cubic feet. The concrete f
kobusy [5.1K]

Answer:

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

Step-by-step explanation:

Given that, a storage shade is be built in the shape of a box with a square base.

Let the height of the box be h and the length of one side of the square base be x.

The area of the square base is = side²

                                                    =x²

The volume of the box is = area of the base × height

                                          =x²h

According to the problem,

x²h=686

\Rightarrow h=\frac{686}{x^2} .......(1)

The concrete for the base costs $5 per square foot.

The material for the base costs =$ 5x²

The material for the roof costs $9 per square foot.

The material cost for roof is =$9x²

The material for the sides costs $3.50  per square foot.

The material cost for sides =$(3.50× 4xh )

                                             =$14xh

Total cost =$(5x²+9x²+14xh)

                =$(14x²+14 xh)

Let

C = 14x²+14 xh

Putting h=\frac{686}{x^2}

C=14x^2+14 x.\frac{686}{x^2}

\Rightarrow C=14x^2+\frac{9604}{x}

Differentiating with respect to x

C'= 28x-\frac{9604}{x^2}

Again differentiating with respect to x

C''= 28+\frac{19208}{x^2}

To find the dimension set C'=0

28x-\frac{9604}{x^2}=0

\Rightarrow 28x=\frac{9604}{x^2}

\Rightarrow x^3=\frac{9604}{28}

\Rightarrow x=7

Now,

C''|_{x=7}= 28+\frac{19208}{7^2}>0

Since at x=7, C''>0, So at x=7 , The cost of material will be minimum.

The height of the box is  h=\frac{686}{x^2}

                                            =\frac{686}{7^2}

                                            =14 foot

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

The cost of the material is =14x^2+\frac{9604}{x}

                                              =14(7)^2+\frac{9604}{7}

                                             =$2,058

6 0
3 years ago
please help me with explanation.I thank all of you for helping me with my math questions.I just need more understanding about th
Bogdan [553]

Answer:

135°

Step-by-step explanation:

Since there are a pair of parallel lines, then

∠3 = ∠1  = 135° ( corresponding angles are congruent )

7 0
3 years ago
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