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3 years ago

How would you write the equation of the graph of this relationship.

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

4 0

We know that y is half of x so x=y(2)

storchak [24]3 years ago

3 0

The Y is multiplying by 2 across the X OR the X’s are being divided by 2
Ex: 3x2=6 OR 6/3=2

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What are the characteristics of the graph of the inequality x < 4.5?

lyudmila [28]

Answer:

see explanation

Step-by-step explanation:

Given x < 5

The graph will have an open circle at 5 indicating that x is not equal to 5, which would be a closed circle.

The ray will move to the left since values less than 5 are to the left of 5

4 0

3 years ago

Read 2 more answers

The function that passes through thepoints (24, 28) and (8,8)Is?

icang [17]

The slope of the line that passes through the points (x1, y1) and (x2,y2) is computed as follows:

$m=\frac{y_2-y_1}{x_2-x_1}$

In this case, the points are (24, 28) and (8,8), then its slope is:

$m=\frac{8-28}{8-24}=\frac{-20}{-16}=\frac{5}{4}$

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept

Substituting into the general equation with m = 5/4 and the point (24, 28) we get:

$\begin{gathered} 28=\frac{5}{4}\cdot24+b \\ 28=30+b \\ 28-30=b \\ -2=b \end{gathered}$

Finally, the equation is

y = 5/4x - 2

3 0

1 year ago

Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Nesterboy [21]

Add the common difference to a term to get the next term.
-10
-10 + (-2) = -12
-12 + (-2) = -14
etc.

The sequence is
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28

3 0

3 years ago

The area of a rectangle is 20 square meters. The length of the rectangle is (x-3) meters and the

babunello [35]

Answer:22fy

Step-by-step explanation:

cause I got it right

6 0

2 years ago

Can anyone answer me this question

yuradex [85]

Question 1:

For this case we have the following functions:

$f (x) = 4x + 1\\g (x) = x ^ 3 + 1$

We must find $g_ {o} f (0$ ):

By definition we have to:

$g_ {o} f = g (f (x))\\f_ {o} g = f (g (x))$

$g (f (x)) = (4x + 1) ^ 3 + 1$

We substitute $x = 0$ :

$g (f (0)) = (4 (0) +1) ^ 3 + 1 = 1 ^ 3 + 1 = 2$

So, we have that $g (f (0)) = 2$

Answer:

$g (f (0)) = 2$

Question 2:

For this case we have the following functions:

$f (x) = 4x + 1\\g (x) = x ^ 3 + 1$

We must find $f_ {o} g (0)$ :

By definition we have to:

$f_ {o} g = f (g (x))\\f (g (x)) = 4 (x ^ 3 + 1) + 1 = 4x ^ 3 + 4 + 1 = 4x ^ 3 + 5$

We substitute $x = 0$ :

$f (g (0)) = 4 (0) ^ 3 + 5 = 5$

Answer:

$f (g (0)) = 5$

Question 3:

For this case we must find the inverse of the following function:

$h (x) = \frac {2x + 1} {3}$

To do this, we follow the steps below:

We change y for $h (x)$ :

$y = \frac {2x + 1} {3}$

We exchange variables:

$x = \frac {2y + 1} {3}$

We clear the value of the variable "y":

$3x = 2y + 1\\3x-1 = 2y\\y = \frac {3x} {2} - \frac {1} {2}$

We change y for $h^{ -1} (x)$ :

$h ^{ - 1} (x) = \frac {3x} {2} - \frac {1} {2}$

Answer:

$h ^ {- 1} (x) = \frac {3x} {2} - \frac {1} {2}$

3 0

4 years ago