Evaluate the following:

Find the solution of the system of equations.

avanturin [10]

Answer:

3

Step-by-step explanation:

The number is 3.

Step-by-step explanation:

Finding the Number

To find the number, we have to translate the problem above to an algebraic equation. The algebraic equation refers to the statement of the equality of two algebraic expressions.

Equation:

Let "x" be the number.

4 is divided by a number - 4/x

3 divided by the number decreased by 2 - 3/x-2

"4 is divided by a number is equal to 3 divided by the number decreased by 2"

4/x = 3/x-2

Solution:

Cross multiply.

4/x = 3/x-2

x(3) = 4(x-2)

3x = 4x - 8

(Combine similar terms.)

3x - 4x = - 8

- x = - 8

- x/- 1 = - 8/- 1

x = 8

Final Answer:

8

Checking:

4/x = 3/x-2

4/8 = 3/8-2

1/2 = 3/6

1/2 = 1/2 ✔

7 0

3 years ago

PLSS HELP ME WITH THIS! 20 POINTS

Svetradugi [14.3K]

Answer:

C)

Step-by-step explanation:

Every $x$ is 6 times bigger than $y$

3 0

2 years ago

Read 2 more answers

An electronics store is selling car chargers for cell phones. The expense function is E = - 300p + 13, 000 and the revenue funct

Brums [2.3K]

Answer:

Wala akong pake kasi ndi naman ako marunong sa math

5 0

3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago

A) -165 °<br> B) -125 °<br> C) 125 °<br> D) 165 °

seropon [69]

Answer:

it might be B, but dont trust me on this one because im not so sure.

Step-by-step explanation:

srry i just dont do this yet i havent rlly learned this but ik a bit abt it so yea. have a great night !

5 0

3 years ago