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Alisiya [41]
3 years ago
9

Evaluate the following:

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
6 0
It is the same as 7-4
7-4=3
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Find the solution of the system of equations.
avanturin [10]

Answer:

3

Step-by-step explanation:

The number is 3.

Step-by-step explanation:

Finding the Number

To find the number, we have to translate the problem above to an algebraic equation. The algebraic equation refers to the statement of the equality of two algebraic expressions.

Equation:

Let "x" be the number.

4 is divided by a number - 4/x

3 divided by the number decreased by 2 - 3/x-2

"4 is divided by a number is equal to 3 divided by the number decreased by 2"

4/x = 3/x-2

Solution:

Cross multiply.

4/x = 3/x-2

x(3) = 4(x-2)

3x = 4x - 8

(Combine similar terms.)

3x - 4x = - 8

- x = - 8

- x/- 1 = - 8/- 1

x = 8

Final Answer:

8

Checking:

4/x = 3/x-2

4/8 = 3/8-2

1/2 = 3/6

1/2 = 1/2 ✔

7 0
3 years ago
PLSS HELP ME WITH THIS! 20 POINTS
Svetradugi [14.3K]

Answer:

C)

Step-by-step explanation:

Every x is 6 times bigger than y

3 0
2 years ago
Read 2 more answers
An electronics store is selling car chargers for cell phones. The expense function is E = - 300p + 13, 000 and the revenue funct
Brums [2.3K]

Answer:

Wala akong pake kasi ndi naman ako marunong sa math

5 0
3 years ago
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
3 years ago
A) -165 °<br> B) -125 °<br> C) 125 °<br> D) 165 °
seropon [69]

Answer:

it might be B, but dont trust me on this one because im not so sure.

Step-by-step explanation:

srry i just dont do this yet i havent rlly learned this but ik a bit abt it so yea. have a great night !

5 0
3 years ago
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