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marissa [1.9K]
2 years ago
7

The nth term of a sequence is 33 - 5n a) Work out the first three terms of the sequence.

Mathematics
1 answer:
levacccp [35]2 years ago
7 0
Answer : 28, 23, 18

To find the ‘nth term’ all you have to do is replace the variable ‘n’ in the equation with the number term you’re looking for.

In this case you’re looking for the first three terms, so you would replace n with the numbers 1, 2, and 3.

This gives you 28, 23, and 18.
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3098 + 5922 + 7024
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The sum of a number and eight is zero
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The area of the triangle above will equal one half of a rectangle that is 5 units long and units wide. (Input only whole numbers
il63 [147K]

Answer:

<h2>Width of the rectangle is 2</h2>

Step-by-step explanation:

A rectangle can is made up of two right angled triangle as shown.

Since area of a rectangle = base * height

Area of one of the triangle = \frac{1}{2}\  * \ area\ of\ the\ rectangle

The length and width of the triangle will be the same as that of the rectangle i.e  5units long and 2units wide

Area of one of the triangle = \frac{1}{2}  * 5 * 2

Area of one of the triangle = 5units²

The area of the triangle above will equal one half of a rectangle that is 5 units long and 2 units wide.

5 0
2 years ago
If a couple were planning to have three​ children, the sample space summarizing the gender outcomes would​ be: bbb,​ bbg, bgb,​
marusya05 [52]

Answer:

(a) The sample space is: S = {bb, bg, gb, gg}

(b) The probability that the couple has two girl children is 0.25.

(c) The probability that the couple has exactly 1 boy and 1 girl child is 0.50.

Step-by-step explanation:

A boy child is denoted by, <em>b</em>.

A girl child is denoted by, <em>g</em>.

(a)

A couple has two children.

The sample space for the possible gender of the two children are:

The couple can have two boys, two girls or 1 boy and 1 girl.

So the sample space is:

S = {bb, bg, gb, gg}

(b)

It is provided that the outcomes of the sample space <em>S</em> are equally likely, i.e. each outcome has the same probability of success.

Compute the probability that the couple has two girl children as follows:

P (2 Girls) = Favorable no. of outcomes ÷ Total no. of outcomes

                =\frac{1}{4} \\=0.25

Thus, the probability that the couple has two girl children is 0.25.

(c)

Compute the probability that the couple has exactly 1 boy and 1 girl child as follows:

P (1 boy & 1 girl) = Favorable no. of outcomes ÷ Total no. of outcomes

                          =\frac{2}{4} \\=0.50

Thus, the probability that the couple has exactly 1 boy and 1 girl child is 0.50.

7 0
3 years ago
Is 10.10 greater than 10.01?
kolbaska11 [484]
Yes, it is 0.09 grater that 10.01
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3 years ago
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