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myrzilka [38]
2 years ago
7

*Pop Quiz*

Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0

Answer:

The father is 59

Step-by-step explanation:

lets say each of the kids are twelve

30*5=150-36=114=59+55

30*5+ 150 the age of everyone in the family added together

12*3= 36 the age of all the kids

150-36=114 the age of the adults added together

we know the mother is 4 years younger than the father so to state off you can take 114 and divide it by two to get what half of it is then take take numbers that are four apart to find the ages that add up to 114.

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5 0
3 years ago
7x − 5 &lt; 13x − 3 <br><br>PLz anyone
Ksju [112]

7x-5<13x-3

Minus 7x

-5<6x-3

then add 3

-2<6x

Then divide -2 by 6 and 6x by 6

-1/3>x

I think thats right

4 0
3 years ago
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Kazeer [188]

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5 0
3 years ago
Country A has a growth rate of 4.9​% per year. The population is currently 4 comma 151​,000, and the land area of Country A is 1
kvv77 [185]

Answer:

There will be one person on 1 square yard of land after 1,892,147.588 years.

Step-by-step explanation:

Continuous exponential growth formula:

P(t)=Pe^{rt}

P(t)= Population after t years.

P= Initial population

r=rate of growth.

t= time in year

Given that,

Growth rate of country A (r)= 4.9% per year=0.049 per year.

Initial population (P)= 151,000.

Land area of country area= 14,000,000,000 square yards.

There will be one person on one  square yard of land.

So, there will be 14,000,000,000  person for 14,000,000,000 square yard of land in country A.

P(t)=14,000,000,000 person

\therefore 14,000,000,000= 151,000 e^{0.049t}

\Rightarrow e^{0.049t}=\frac{ 14,000,000,000}{ 151,000}

Taking ln both sides

\Rightarrow ln|e^{0.049t}|=ln|\frac{ 14,000,000,000}{ 151,000}|

\Rightarrow {0.049t}=ln|\frac{ 14,000,000,000}{ 151,000}|

\Rightarrow t}=\frac{ln|\frac{ 14,000,000,000}{ 151,000}|}{0.049}

\Rightarrow t}=1,892,147.588 years

There will be one person for every square yard of land after 1,892,147.588 years.

7 0
3 years ago
What is the range of this equation? f(x) = x + 41 – 2
Sergeu [11.5K]
The range is the set of all valid
y
y
values. Use the graph to find the range.
Interval Notation:
(
−
∞
,
∞
)
3 0
2 years ago
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