What is the midpoint of a segment whose endpoints are (-3, -3) and (-13, -13)

There are two aquariums in a science room. One of the aquariums is 18 inches wide, 25 inches long, and 12 inches high. If there

erma4kov [3.2K]

Answer:

23 (rounded) (You can't overflow a fish take Or what would be the point of the tank.)

Step-by-step explanation:

The unrounded answer is 23.376623376623376623376623376623.

7 0

2 years ago

In the coordinate plane, you are given JKL with J(2, 3), K(10,4), and L(6, 10). Using the distance formula, classify JKL

Marrrta [24]

Answer:

Perimeter of JKL = 22.55 unit (Approx.)

Step-by-step explanation:

Given:

Coordinate of J = (2,3)

Coordinate of K = (10,4)

Coordinate of L = (6,10)

Find:

Perimeter of JKL

Computation:

Distance = √(x1 - x2)² + (y1 - y2)²

Distance between JK = √(2 - 10)² + (3 - 4)²

Distance between JK = √64 + 1

Distance between JK = √65

Distance between JK = 8.06 unit

Distance between KL = √(10 - 6)² + (4 - 10)²

Distance between KL = √16 + 36

Distance between KL = √52

Distance between KL = 7.21 unit

Distance between LJ = √(6 - 2)² + (10 - 3)²

Distance between LJ = √4 + 49

Distance between LJ = √53

Distance between LJ = 7.28 unit

Perimeter of JKL = Distance between JK + Distance between KL + Distance between LJ

Perimeter of JKL = 8.06 + 7.21 + 7.28

Perimeter of JKL = 22.55 unit (Approx.)

4 0

2 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

PLEASE HELP ITS MATH THANK YOUUUU

ioda

Answer:

35 : w = 1 : 2

obviously w = 70

Step-by-step explanation:

Hopefully this helps you :)

Have a nice day.

apokibunnyavatar

6 0

2 years ago

A gardener works for 13 hours during a week and charges $169 how much does the gardener charge for each hour?

bonufazy [111]

Answer:

You have to divide to unit price, 169/13 is equal to 13!

Step-by-step explanation:

7 0

2 years ago