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Mekhanik [1.2K]
3 years ago
11

If y varies directly with x and y = 16 when x = 4, find x when y = 8.

Mathematics
2 answers:
VladimirAG [237]3 years ago
7 0

Answer: X = 2

Step-by-step explanation:

Y & X

Y = KX

K = Y/X = 16/4 = 4

Y= 8

K =4

X=?

X = Y/K

X = 8/4 = 2

Luba_88 [7]3 years ago
5 0

Step-by-step explanation:

Given:  \\ y \:  \alpha  \: x \\  \therefore \: y = kx..(k = constant)..(1) \\  \\ let \: us \: substitute \: x = 4 \: and \: y = 16 \:  \\  in \: equation \: (1)\\  \\ 16 = 4k \:  \\  \implies \: k =  \frac{16}{4}   \\  \implies \: k =  4 \\ substituting \: k = 4 \: in \: equation \:  \\ (1) \: we \: find :  \\ y = 4x....(2) \\ now \: we \: need \: to \: find \: x \: when \: y = 8 \\   \therefore \: 8 = 4x \\  \implies \: x =  \frac{8}{4}  \\   \huge \orange{ \boxed{\implies \: x =  2}}

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(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

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8 0
3 years ago
Find the tenth term in each sequence. -1,2/3,7/3,4,17/3
Luba_88 [7]

It'a an arithmetic sequence:

a_1=-1\\\\a_2=-1+\dfrac{5}{3}=-\dfrac{3}{3}+\dfrac{5}{3}=\dfrac{2}{3}\\\\a_3=\dfrac{2}{3}+\dfrac{5}{3}=\dfrac{7}{3}\\\\a_4=\dfrac{7}{3}+\dfrac{5}{3}=\dfrac{12}{3}=4\\\\a_5=4+\dfrac{5}{3}=\dfrac{12}{3}+\dfrac{5}{3}=\dfrac{17}{3}\\\vdots\\\\\text{The general formula for nth term of an arithmetic sequence}\\\\a_n=a_1+(n-1)d\\\\\text{We have}\ a_1=-1\ \text{and}\ d=\dfrac{5}{3}.\\\\\text{Substitute}\\\\a_n=-1+(n-1)\left(\dfrac{5}{3}\right)=-1+\dfrac{5}{3}n-\dfrac{5}{3}=\dfrac{5}{3}n-\dfrac{3}{3}-\dfrac{5}{3}

\boxed{a_n=\dfrac{5}{3}n-\dfrac{8}{3}}

5 0
2 years ago
Three vertices of parallelogram WZXY are W(-5, 2), X(2, 4) and Z(-7, -3). Find the coordinated of the vertex, Y.
Dominik [7]

Answer:

Y = (4,9)

Step-by-step explanation:

Given

W(x_1,y_1) = (-5, 2)

Z(x_4,y_4) = (-7, -3)

X(x_2,y_2) = (2, 4)

Required

Find Y

To do this, we make use of the mid-point formula

i.e.

M = \frac{1}{2}(x_n+x_m,y_n+y_m})

WX and ZY are the diagonals of the parallelogram.

The mid-point of WX is:

M = \frac{1}{2}(-5+2,2+4)

M = \frac{1}{2}(-3,6)

The mid-point of ZY is:

M = \frac{1}{2}(-7+x,-3+y)

Equate both values of M

\frac{1}{2}(-3,6) = \frac{1}{2}(-7+x,-3+y)

Multiply both sides by 2

(-3,6) = (-7+x,-3+y)

By comparison:

-7 + x = -3

-3 + y = 6

-7 + x = -3

x = 7 -3

x = 4

-3 + y = 6

y = 6 +3

y = 9

Hence:

Y = (4,9)

3 0
2 years ago
5b=21<br> Reduce the fraction
vlabodo [156]

Answer:

21/5

Step-by-step explanation:

5 0
3 years ago
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amm1812
Since we are adding two positive numbers here, their sum could be found by writing either

 8
+4
---               
12

or

 
  4
+8
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12
6 0
2 years ago
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