Which lines, if any, must be parallel based on the given information

Mathematics

1 answer:

pav-90 [236]3 years ago

3 0

Lins a and d i think. dont quote me

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Solve the following inequality:<br> ALGEBRA 1

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Answer:

$m \leqslant 10 \: or \: m > 4$

Step-by-step explanation:

$\frac{m - 2}{3} \leqslant - 4 \\ \frac{m - 2}{3} \times 3 \leqslant - 4 \times 3 \\ m - 2 \leqslant - 12 \\ m - 2 + 2 \leqslant - 12 + 2 \\ m \leqslant 10$

$3m - 8 > 4 \\ 3m - 8 + 8 > 4 + 8 \\ 3m > 12 \\ \frac{3m}{3} > \frac{12}{3} \\ m > 4$

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The sum of an integer and its _____ inverse is 0.

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Angelina_Jolie [31]

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Step-by-step explanation:

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3 years ago

Rationalize the denominator of square root of negative 16 over open parentheses 1 plus i close parentheses plus open parentheses

emmasim [6.3K]

$\bf \cfrac{\sqrt{-16}}{(1+i)+(6+3i)}\implies \cfrac{\sqrt{-1\cdot 16}}{1+i+6+3i}\implies \cfrac{\sqrt{-1}\cdot \sqrt{16}}{7+4i}
\\\\\\
\cfrac{i\cdot \sqrt{4^2}}{7+4i}\implies \cfrac{4i}{7+4i}\impliedby 
\begin{array}{llll}
\textit{now, we'll multiply by the}\\
\textit{conjugate of the denominator}
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{and recall }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
\textit{also recall that }i^2=-1
\\\\
-------------------------------\\\\$

$\bf \cfrac{4i}{7+4i}\cdot \cfrac{7-4i}{7-4i}\implies \cfrac{4i(7-4i)}{(7+4i)(7-4i)}\implies \cfrac{28i-16i^2}{7^2-(4i)^2}
\\\\\\
\cfrac{28i-16(-1)}{49-(4^2i^2)}\implies \cfrac{28i+16}{49-[16(-1)]}\implies \cfrac{16+28i}{49+16}\implies \cfrac{16+28i}{65}
\\\\\\
\cfrac{16}{65}+\cfrac{28i}{65}$

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4 years ago