Answer:
Step-by-step explanation:
The two dump intervals have a greatest common factor (GCF) of 3, so their least common multiple (LCM) is ...
(18)(21)/3 = 126 . . . . minutes
This period is 2 hours 6 minutes. The last time both dumped was 1:10, so the next time both will dump is ...
1:10 +2:06 = 3:16 . . . P.M.
and the next time after that is ...
3:16 +2:06 = 5:22 . . . P.M.
Please, find the solution atached in JPG format
A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
</span>
If you subtract 16 on both sides... x will be alone. Therefore 51-16=35
x=35 (B)
