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Marat540 [252]
3 years ago
5

A spherical ball with a volume of 972π in.3 is packaged in a box that is in the shape of a cube. The edge length of the box is e

qual to the diameter of the ball. What is the volume of the box?
Mathematics
1 answer:
aivan3 [116]3 years ago
4 0
To find the volume of the box you will use the volume of the sphere formula to find the radius of the circular region of the sphere. You wil then double the radius to find the diameter.

V = 4/3 x pi x r^3
972 x pi= 4/3 x pi x r^3
729 = r^3
The cubic root of 729 is 9 because 9 x 9 x 9 = 729.

The radius is 9 inches, and the diameter is 18 inches.

The volume of the box is 18 in x 18 in x 18 in or 5832 in.³.
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The correct two-way frequency table for the data is <u>Men </u><u>and </u><u>Women </u><u>Leisure Time Activity Preferences.</u>

<h3>What is a correct two-way frequency table?</h3>

A correct two-way frequency table displays frequencies for two categories (rows and columns) collected from categorical variables (men and women).

Men and Women Leisure Time Activity Preferences;

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Men                  11                         3                          6                          20

Women             5                       16                          9                          30

Column totals 16                       19                         15                          50

Hence, the correct two-way frequency table for the data is Men and Women Leisure Time Activity Preferences.

To learn more about two-way frequency tables click the link given below.

brainly.com/question/4555163

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Step-by-step explanation:

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Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

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d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

For triangle ABC, we have:

AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4

BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5

CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2

For triangle DEF, we have:

DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2

EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5

FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1

Divide corresponding sides of the triangles to calculate the scale factor k

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Evaluate the quotients

k = 2 = 2 = 2

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

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