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Cerrena [4.2K]
3 years ago
15

Which expression is equivalent to 16+8? A.2{8+4} B.4{4+8} C.4{4+1} D.2{8+5}

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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Last season Ellen and Janet together won 32 tennis matches Ellen won 6 more than then Janet How many more matches did Ellen win
barxatty [35]
Answer : 22

32/2=16 +6 =22
32-22=10 —> how many matches janet won
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4. If a function, f(x) is shifted to the left four units, what function represents the transformation?. A. f(x-4). B. f(x) - 4.
Nana76 [90]

If a function, f(x) is shifted to the left four units, the function that represents the transformation would be f(x+4). The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query about and it will be able to help you.

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Simplify to using laws of exponents<br><br> (-2)^2(-2)^5
MAVERICK [17]

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-128

Step-by-step explanation:

(-2)^2  *  (-2)^5 <---

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(-2)^7<----

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Find the Perimeter of the figure below, composed of a rectangle and a semicircle.
Korolek [52]

Answer:

20.3

Step-by-step explanation:

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7 0
2 years ago
Data on IQ for 33 first graders are given as follows: 82, 96, 99, 102, 103, 103, 106, 107, 108, 108, 108, 108, 109, 110, 110, 11
Dahasolnce [82]

Answer:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

Where n represent the sample size, on this case n =33. If we use this formula we got:

\bar X = 113.727

And for this case we know that is the best estimator since is an unbiased estimator for the true population mean since we have this:

E(\bar X) = E(\frac{\sum_{i=1}^n x_i}{n})= \frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n} = \mu

Step-by-step explanation:

For this case we have the following values given:

82, 96, 99, 102, 103, 103, 106, 107, 108, 108, 108, 108, 109, 110, 110, 111, 113, 113, 113, 113, 115, 115, 118, 118, 119, 121, 122, 122, 127, 132, 136, 140, 146

And we want to estimate the mean value of IQ for the conceptual population.

For this case we can use as estimator for the population mean the sample mean. We know that the sample mean is given by this formula:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

Where n represent the sample size, on this case n =33. If we use this formula we got:

\bar X = 113.727

And for this case we know that is the best estimator since is an unbiased estimator for the true population mean since we have this:

E(\bar X) = E(\frac{\sum_{i=1}^n x_i}{n})= \frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n} = \mu

5 0
3 years ago
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