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Paraphin [41]
3 years ago
8

F(x) = – 2x^2+ 6x + 1 Find f (6)

Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

f(6) = -2(6)² + 6(6) + 1

f(6) = -72 + 36 +1

f(6) = -35

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How do u do ratio? I don't understand
Monica [59]
A ration is basically a fraction. It can be written different ways i.e. 2/3 or 2:3. They are both the same thing. There are 5 girls out of 39 students... ratio= 5/39 or 5:39
8 0
3 years ago
Craig solicited donations for his school's jump-rope a-thon. He collected $13.00 in fixed donations and pledges totaling $1.50 f
charle [14.2K]

Answer:

25

Step-by-step explanation:

13+1.50m

13+1.50(8)

13+12

25

8 0
2 years ago
Question 15 of 40
PilotLPTM [1.2K]

Answer:

Option C: n = 32; p^ = 0.4

Step-by-step explanation:

The normal curve can be used in this case if; np ≥ 10 or n(1 - p) ≥ 10

A) For n = 28 and p = 0.3;

np = 28 × 0.3 = 8.4 < 10

Thus, it can't be used.

B) For n = 28 and p = 0.9;

np = 28 × 0.9 = 25.2 > 10 Ok

n(1 - p) = 28(1 - 0.9) = 2.8 Not Ok

Thus, it can't be used

C) For n = 32 and p = 0.4

np = 32 × 0.4 = 12.8 > 10 Ok

n(1 - p) = 32(1 - 0.4) = 19.2 > 10 Ok

Thus, it can be used

D) For n = 32 and p = 0.2

np = 32 × 0.2 = 6.4 < 10 Not Ok

Thus it can't be used.

4 0
3 years ago
F(x)=x^2-1 <br> G(x)=x-1 <br> find (f+g)(10).
WARRIOR [948]
<h2>Adding Functions</h2><h3>Answer:</h3>

(f +g)(10) = 108

<h3>Step-by-step explanation:</h3>

Before we can solve for (f +g)(10), we need to know how (f +g)(x) is defined.

(f +g)(x) = f(x) +g(x) \\ (f +g)(x) = (x^2 -1) +(x -1) \\ (f +g)(x) = x^2 -1 +x -1 \\ (f +g)(x) = x^2 +x -2

We can now solve for (f +g)(10):

(f +g)(10) = (10)^2 +(10) -2 \\ (f +g)(10) = 100 +10 -2 \\ (f +g)(10) = 108

6 0
3 years ago
Csc\theta -cot\theta =\frac{sin}{1+cos\theta }
Inga [223]

Answer:

Step-by-step explanation:

Left Hand Side

Change to sin(theta) and cos(theta)

csc(theta) = 1/sin(theta)

cot(theta) = cos(theta)/sin(theta)

1/sin(theta) - cos(theta)/sin(theta)                   Put over Sin(theta) Common denominator

[1 - cos(theta)] / sin(theta)                                Multiply numerator and denominator by 1 + cos(theta)

(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))

(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)

sin^2(theta) / (sin(theta)* ( 1 + cos(theta)

sin(theta) / (1 + cos(theta) )

Right hand Side.

See Above.

4 0
3 years ago
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