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Flauer [41]
2 years ago
8

Find the distance between pair of points (0, - 5) and (7, 2) . necessary , express the answer in radical form and then round to

two decimal places

Mathematics
1 answer:
kifflom [539]2 years ago
6 0

Answer:

d=9.899495 or √98

Step-by-step explanation:

√(7-0)^2 + (2-(-5))^2

√(7)^2+(7)^2

√98

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I need help with solving this problem for my geometry homework.
maxonik [38]

Answer:

x = 5

y = 23

Step-by-step explanation:

32x - 70 = 90

32x = 160

x = 5

16y + 92 = 13y + 161

3y = 69

y = 23

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3 years ago
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4 0
2 years ago
To receive a grade of A on an 80-question test, 90% of the questions must be answered correctly. What is the maximum number of q
marta [7]

Answer:

The answer would be 8.

Step-by-step explanation:

This is a percentage question, and I have struggled with these before but this is the <em>easiest</em> way to solve it given these certain criteria.

Alright, so it's given that:

A) 90%= an A grade

and

B) This is an 80-question test.

Given these, we can do the following:

90% times 80, which equals <em>72</em>.

Just to check, we know that to convert percentages to fractions, we move the decimal two spots to the left, therefore 90%= 0.90, or 0.9. We take 72 and divide it by 80, and we get 0.9, thus showing that it is correct.

Then, we do 80-72 and using simple math we get 8.

8 0
3 years ago
1) Television sizes are a measurement of the length of a TV's diagonal. If a 65-inch TV has
sammy [17]

Answer:

56.7 inches

Step-by-step explanation:

7 0
3 years ago
Can someone be so freaking awesome and help me out with the correct answer please :( !?!?!?!?!???!!! 30 points!!!
Sindrei [870]

\bf 7~~,~~\stackrel{7+6}{13}~~,~~\stackrel{13+6}{19}~~,~~\stackrel{19+6}{25}\qquad \impliedby \qquad \textit{common difference "d" is 6}

we know all it's doing is adding 6 over again to each term to get the next one, so then

\bf \stackrel{\textit{Recursive Formula}}{\stackrel{\textit{nth term}}{f(n)}~~=~~\stackrel{\textit{the term before it}}{f(n-1)}~~~~\stackrel{\textit{plus 6}}{+~~~~6}}

now for the explicit one

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=7\\ d=6 \end{cases} \\\\\\ a_n=7+(n-1)6\implies a_n=7+6n-6\implies \stackrel{\textit{Explicit Formula}}{\stackrel{f(n)}{a_n}=6n+1} \\\\\\ therefore\qquad \qquad f(10)=6(10)+1\implies f(10)=61

3 0
3 years ago
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