Answer:
Step-by-step explanation:
AS we can see the lines are parallel so
2 ( 4x - 3) + 7(x + 3) = 180° ( being so - interior angles)
8x - 6° + 7x + 21° = 180°
15x + 15° = 180°
15x = 180° - 15°
15x = 165°
x = 165° / 15
Therefore x = 11°
Now
2 ( 4x - 3) = 2 ( 4 * 11° - 3°) = 2 ( 44 - 3)° = 2* 41 = 82°
7(x + 3 ) = 7 ( 11° + 3°) = 7 * 14 = 98°
We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.
The answer is 0.1492.
Answer:
Step-by-step explanation:
<h3>A.</h3>
The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>
The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
The complete question in the attached figure
Part a)
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm
the answer part a) isAB=6 cmPart b)
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³
the answer part b) is 100 cm³