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telo118 [61]
2 years ago
13

A box contains 2 plain pencils and 2 pens. A second box contains 3 color pencils and 5 crayons. One item from each box is chosen

at
random. What is the probability that a pen from the first box and a crayon from the second hoy are selected?
Mathematics
1 answer:
Lapatulllka [165]2 years ago
8 0

Answer:

50% pen first box and 62.5% crayon from second box

Step-by-step explanation:

The first box contains 4 items, 2 of each. This means there are \frac{2}{4} pens. This gives you a \frac{2}{4} chance of picking out a pen. This can be written as 50%.

The second box contains 8 items, 3 color pencils and 5 crayons. This means \frac{5}{8} of the contents are crayons, meaning you have a \frac{5}{8} or 62.5% chance of picking a crayon.

*For working out the percentages, you should convert the fraction to a decimal and then multiply that by 100.

**This content involves fractions, decimals and percentages, as well as basic probability, which you may want to revise. I'm always happy to help!

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The sum of three consecutive numbers is 276. What is the smallest of these intengers?
shtirl [24]

Answer:

91

Step-by-step explanation:

Let x be the smallest one:

● x is the first number

● x+1 is the second number

● x+2 is the third number

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3 years ago
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Step-by-step explanation:

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3 years ago
Please help me please I reallly need help
kiruha [24]

Answer:

we have:

v  =  \frac{1}{3} \pi \: r {}^{2}h \\  \\  =  > 60\pi =  \frac{1}{3} \pi \: r {}^{2} h \\  \\  <  =  > 180 = r {}^{2} h

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h = 5 r = 6=> d = 12

3 0
3 years ago
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