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klemol [59]
3 years ago
10

If there are five choices on a multiple choice test, what is the probability of guessing any of them correctly?

Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0
C. 1/5. Because there is only one answer that is the right answer to each multiple choice. Also, there are 5 choices for us to choose.
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Can someone solve this?
inn [45]

Answer:

1. 15 degrees.

2. 90 degrees.

3. 66 degrees.

Step-by-step explanation:

M and 2 appear to be 90 degrees. This is because there are parallel sides on the left and right of the kite. So, 2 is 90 degrees.

E and 75 are corresponding (I don't remember the postulate or whatnot) so 90 degrees plus 75 degrees is 165 degrees. There are 180 degrees in a triangle, so 180 minus 165 is 15. 1 Has to be 15 degrees.

3 is 66 degrees since it is corresponding with the angle on the other side of T (I, once again, do not remember the postulate).

6 0
3 years ago
Answer urgent please!!
butalik [34]

Answer:

  • 15

Step-by-step explanation:

u=5i-j\\\\v=3i+j\\\\w=i+4j\\

v+w

3i+j+i+4j\\\\4i+5j\\\\u*(v+w)\\\\(5i-j)(4i+5j)\\\\20-5\\\\\boxed{15}

~

4 0
2 years ago
Bridgette made a graph of her neighborhood on a coordinate grid. The points A(-2, 3), B(-2, -2), C(2, -2), and D(2, 3) represent
vodka [1.7K]

Answer:

\boxed{\text{18 blocks}}

Step-by-step explanation:

Distance travelled on graph = AB + BC + CD + DA  

AB = CD  = (3 +2) = 5

BC = AD = 2 –(-2) = 4

Distance on graph = 2 × 5 + 2 × 4 = 10 + 8 = 18 spaces = 18 blocks

Bridgette jogs \boxed{\textbf{18 blocks}}each day.

8 0
3 years ago
I will give a thanks
gogolik [260]
Do what is in the parentheses then add
7 0
3 years ago
The perimeter of the kitchen is 528 inches if the width of the kitchen is 120 inches what is the length of the kitchen
butalik [34]

Answer: 144 inches.


Step-by-step explanation:

1. To solve this problem you must remember the formula for calculate the perimeter of a rectangle, which is shown below:

P=2l+2w

Where l is the lenght and w is the width.

2. You know the perimeter and the width, then you can solve for the length, as following:

P-2w=2l\\l=\frac{P-2w}{2}\\l=\frac{(528in)-(2*120in))}{2}\\l=144in



7 0
3 years ago
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