Least: game two
greatest: game one
Even though both games have over 14,000, game two outdoes game one by being least because 505 is smaller than 753.
Answer: D
Step-by-step explanation:
To find the perimeter of the square, you want to first find the length of each side. Since the figure is a square, we know that each side is equal to each other. We can set the expressions equal to each other to find x.
[subtract both sides by 1/2x]
[add both sides by 1]
[multiply both sides by 4]

Now that we know x, we can plug it into each expression to find teh length of each side.
[multiply]
[subtract]

Now that we know each side is equal to 23, we can add all the sides together to find the perimeter.
23+23+23+23=92 or 23×4=92
Since we know that the perimeter is 92 units, the answer is D.
2/5 = x/30......2 in to 5 sec = x in to 30 sec
cross multiply
5x = 60
x = 60/5
x = 12 inches <==
A is aldult tickets
b is child tickets
b = 2/3 a
7a + 12b = 90
7a + 12 x 2/3 a = 90
7a + 8a = 90
15a = 90
a = 6; b = 4
20 total marbles....7 are green
probability on first draw is 7/20...and since the marble was not replaced, the probability on the second draw is 6/19. And since they cant happen at the same time, we multiply
7/20 * 6/19 = 42/380 which reduces to 21/190