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2 years ago

The circumference of a circle is 22π in. What is the area, in square inches? Express your answer in terms of π

Mathematics

1 answer:

charle [14.2K]2 years ago

4 0

Answer:

A = 121 pi in^2

Step-by-step explanation:

The circumference is given by

C = 2 * pi*r

22 pi = 2 * pi *r

Divide each side by 2 pi

22 pi / (2 pi) = 2 pi r / (2pi)

11 = r

Now find the area

A = pi r^2

A = pi (11)^2

A = 121 pi in^2

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AlladinOne [14]

Answer:

x=5

Step-by-step explanation:

3.2x+4=20

Subtract 4 from both sides

3.2x=16

divide by 3.2

x=5

4 0

3 years ago

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A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago

A museum curator is hanging 7 paintings in a row for an exhibit. There are 4 Renaissance paintings and 3 Baroque paintings. From

Marina CMI [18]

Answer:

144 ways

Step-by-step explanation:

Number of paintings = 7

Renaissance = 4

Baroque = 3

We are hanging from left to right and we will first hang Renaissance painting before baroque painting.

For Renaissance we have 4! Ways of doing so. 4 x3x2x1 = 24

For baroque we have 3! Ways of doing so. 3x2x1 = 6

We have 4!ways x 3!ways

= (4x3x2x1) * (3x2x1) ways

= 144 ways

Therefore we have 144 ways to hang the painting.

6 0

3 years ago

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Alexandra [31]

CALCULATOR! Sorry but I mean....really?

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3 years ago

WHAT THE ANSWER FOR THIS QUESTION? C = { X|X + 6 = 10}

Solnce55 [7]

Given that C = { X | X + 6 = 10}

This can be interpreted grammatically as "C is a set X such that X is the solution to X + 6 = 10".

Given that X + 6 = 10
X = 10 - 6 = 4

Therefore, the solution is
C = {4}

7 0

3 years ago