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2 years ago

A basketball player made 80 out of 100 attempted free throws. What percent of free throws was made?

Mathematics

2 answers:

sweet [91]2 years ago

8 0

Answer:

80%

Step-by-step explanation:

Mrac [35]2 years ago

5 0

Percent of free throws = (number of free throws made / total attempts) x 100

Percent = (80/100) x 100 = 80%

The answer is 80%

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The triangular numbers are defined by the recursive formula t1 = 1, tn = tn - 1 + n, where n ∈N and n > 1. What are the first

GalinKa [24]

ANSWER

C) 1, 3, 6, 10, 15, 21, 28, 36, 45

EXPLANATION

The recursive formula is,

$t_1=1,t_n=t_{n-1}+n$

when n is a natural number greater than 1.

When n=2,

$t_2=t_{2-1}+2$

$t_2=t_{1}+2 = 1 + 2 = 3$

when n=3,

$t_3=t_{2}+2 = 3 + 3= 6$

when t=4,

$t_4=t_{3}+2 = 6+ 4= 10$

When t=5,

$t_5=t_{4}+5 = 10 + 5 = 15$

when t=6,.

$t_6=t_{5}+6 = 15 + 6 = 21$

when t=7

$t_7=t_{6}+7 = 21 + 7 = 28$

When t=8,

$t_8=t_{7}+8 = 28 + 8 = 36$

When t=9,

$t_9=t_{8}+9 = 36 + 9 = 45$

Hence the first nine triangular number are

C) 1, 3, 6, 10, 15, 21, 28, 36, 45

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2 years ago

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2 years ago

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Step-by-step explanation:

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2 years ago

A basketball player made 80 out of 100 attempted free throws. What percent of free throws was​ made?

A basketball player made 80 out of 100 attempted free throws. What percent of free throws was made?