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Ivan
3 years ago
10

Solve for x: dx+fx=8-2dx

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer:

fx=8-3dx

Step-by-step explanation:

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Can somebody explain how to do this question
evablogger [386]

Answer:

The answer is D

Step-by-step explanation:

Remember:

Contrapositive means that if you reverse the hypothesis and the conclusion the statement will mean the same thing

7 0
2 years ago
A train covers a distance of 80 miles in 2 hours. At this rate, about how many hours will it take to cover a distance of 200 mil
Vadim26 [7]
Let's write miles over hours
80 / 2 = 200/ x
cross multiply
80x = 400
divide both sides by 80
x = 5

It will take 5 hours to cover 200 miles

Hope this helps :)
6 0
3 years ago
Pls help if you actually can
Setler79 [48]

The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

<h3>How to identify similar triangles?</h3>

From the image attached, we see that we are given the Parallelogram GRPC. Thus;

A.  The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;

∠CGB ≅ ∠PEB  (Alternate Interior Angles)

∠BPE ≅ ∠BCG  (Alternate Interior Angles)

∠GBC ≅ ∠EBP  (Vertical Angles)

C.  To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;

225/325 = PE/375  

PE = 260 ft

BE/425 = 225/325  

BE = 294 ft

Read more about Similar Triangles at; brainly.com/question/14285697

#SPJ1

5 0
2 years ago
The surface area of a cube is 24 square inches.<br> What is the side length of the cube?
Alex777 [14]

Answer:

2 inches

Step-by-step explanation:

A cube has 6 faces. Therefore, each face is 4 square inches. (24/6) The side length of the square (face of the cube) is the square root of the area. The square root of 4 is 2. There is your answer :)

3 0
3 years ago
From our lesson, what is your difficulty in dealing with exponential expressions?
aleksandrvk [35]

Answer:

From the said lesson, the difficulty that I have been trough in dealing over the exponential expressions is the confusion that frequently occurs across my system whenever there's a thing that I haven't fully understand. It's not that I did not actually understand what the topic was, but it is just somewhat confusing and such. Also, upon working with exponential expressions — indeed, I have to remember the rules that pertain to dealing with exponents and frequently, I will just found myself unconsciously forgetting what those rule were — rules which is a big deal or a big thing in the said lesson because it is obviously necessary/needed over that matter. Surely, it is also a big help for me to deal with exponential expressions since it's so much necessary — it's so much necessary but I keep fogetting it.. hence, that's why I call it a difficulty. That's what my difficulty. And in order to overcome that difficulty, I will do my best to remember and understand well the said rules as soon as possible.

3 0
2 years ago
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