Let x = software program
Let y = video game
x < 200 ; y < 300
x + y < 425
50x ; 35y
x = 200 ; y = 225
50(200) + 35(225) = 10,000 + 7,875 = 17,875
x = 125 ; y = 300
50(125) + 35(300) = 6,250 + 10,500 = 16,750
x = 175 ; y = 250
50(175) + 35(250) = 8,750 + 8,750 = 17,500
It is more profitable to maximize production of software program when working within the limits provided.
Answer: a) P = 0.5, b) P = 0.07
Step-by-step explanation:
Hi!
Lets call X₁ the time at which you arrive, and X₂ the time at which Bob arrives. Both are random variables with uniform density in the interval [0, 60] (in minutes). Their joint distribuition is uniform over the square in the image, with value P = 1/(60*60) = 1/3600.
a) For you to get more cake than Bob, you should arrive earlier. This event is A = { X₁ < X₂ }, the shaded triangle in the figure.The area of this event (set) is half the total area of the square, so P(A) = 0.5.
It makes sense, beacuse its equally probable for you or Bob to arrive earlier, as both have uniform density over the time interval.
b) In this case you arrive later than Bob, but less than 5 minutes later. So the event is B = { X₂ < X₁ < (X₂ + 5) } . This is the gray shaded area in b) part of the image. Its area is the difference two triangles (half square - blue triangle), then the probability is:

Answer:
He ate 42 of the 90 grapes in the bowl
The percentage of grape he ate will be given as this:
42/90 * 100%
=46.67%
Tyler has ate 46.67% of the grapes
Th three numbers he could of had on his uniform are 60 30 or 90
Answer:
Step-by-step explanation:
24 foot