Answer:
A' (3/2, -9/4)
B' (-3, 9/4)
C' (3/2, 9/4)
Step-by-step explanation:
1. You have the following coordinates of the vertices of the triangle ABC:
A (-2, 3) B (4, -3) C (-2, -3)
2. The given scale factor is -3/4, therefore, to calculate the coordinates of the triangle A'B'C', you must multiply each coordinate of the triangle ABC by the scale factor.
3. Therefore, you obtain that the the coordinates of the triangle A'B'C' are:
A'=((-2)(-3/4), (3)(-3/4))=(3/2, -9/4)
B'=(4(-3/4), (-3)(-3/4))=(-3, 9/4)
C'=((-2)(-3/4), (-3)(-3/4))=(3/2, 9/4)
Answer:
40
Step-by-step explanation:
a^2+b^2=c^2
therefore c^2-b^2=a^2
41x41=1681
9x9=81
1681-81=1600
Sqrt1600=40
Answer:
8 Units, let me know if you didn't understand anything.
Step-by-step explanation:
Translation is the simple movement of just left, right, up or down. when dealing with the absolute value function here are the transformations.
A|B(x - C)| + D where A is the vertical stretch that multiplies all y values by A save where y=D. B is the horizontal shrink, so you divide all x values by B except for where x=C. C is the horizontal shift, which is a translation. C makes ALL points on the graph move to the right by C or if C is negative it moves them to the left. it could also look like |x + C|. keep in mind, +C is actually -C because - -C = C. D shifts up and down, so it is also a translation. if D is positive it moves up and if D is negative it moves down.
Nowthe only transformation in your problem is -8, which is a horizontal shift to the right. so the graph moves 8 to the right. There is your answer, 8 units.
Answer:
Omg
Step-by-step explanation:
