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3 years ago

Isolate the variable on the following problem. show your work.3a+3=6

Mathematics

1 answer:

Svetach [21]3 years ago

7 0

Answer:

3a=6-3

Step-by-step explanation:

if you have the equation 3a + 3 = 6, you have to move 3 to the other side of the equation to isolate it. To do this, you subtract 3 from both sides giving you 3a=6-3

Hope this helped

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I really dont know this

Elena L [17]

Answer:

your answer is b 8/10 - 5/10

Step-by-step explanation:

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2 years ago

Alissa is analyzing an exponential growth function that has been reflected across the y-axis. She states that the domain of the

NeX [460]

Answer:

C) Simon is correct because even though the input values are opposite in the reflected function, any real number can be an input.

================

The exponential growth function has:

Domain - all real numbers,
Range - all real numbers excluding zero.

When the function is reflected across the y-axis, we'll have no change to domain or range from what is described above.

Alissa is correct, the input values change to opposite, however the domain stays same - all real numbers.

It means Simon is correct with his statement.

The matching answer choice is C.

5 0

2 years ago

Read 2 more answers

Erica used friendly numbers to find 43-19 she added 1 to 19 and subtracted 1 from 43 what is erica's error? Explain

Vesnalui [34]

Answer:

She didn't add 1 to 43 as well.

Step-by-step explanation:

I she wants to use friendly numbers, she must do the same thing to both numbers

6 0

3 years ago

Value of the Line integral of xe^y dx over arc of x=e^y from pt (1,0) to (e,1). Please don't bother if you don't know how to do

irina [24]

Parametize C of the line integral as
$({e}^{t} ,t)$
from 0<=t<1 then
$dx = {e}^{t} dt$
which means by substituting x with e^t and y with and dx with e^t dt we get
$integral \: from \: 0 \: to \: 1( {e}^{t} \times {e}^{t} \times {e}^{t} \: dt )$
by adding exponents
$integrl \: from \: 1 \: to \: 0 \: of \: ( {e}^{3t}dt )$
$\frac{ {e}^{3} - 1}{3} - \frac{ {e}^{0} - 1 }{3}$

3 0

3 years ago

Tessa bought stock in a restaurant for $278.00. Her stock is now worth $339.16. What is the percentage increase of the value of

Natasha2012 [34]

The percentage increase of the value of Tessa's stock is 22%

Step-by-step explanation:

The percentage of increase = $\frac{New-old}{old}$ × 100%, where:

New: is the value after increasing
Old: is the value before increasing

Tessa bought stock in a restaurant for $278.00.

Her stock is now worth $339.16

We need to find the percentage of increase of the value of

Tessa's stock

∵ The initial value of the stock = $278.00

∴ The value of the stock after increasing = $339.16

- Substitute these values in the rule above

∴ The percentage of increasing = $\frac{339.16-278}{278}$ × 100%

∴ The percentage of increasing = 0.22 × 100%

∴ The percentage of increasing = 22%

The percentage increase of the value of Tessa's stock is 22%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

8 0

3 years ago

Isolate the variable on the following problem. show your work.3a+3=6​

Isolate the variable on the following problem. show your work.3a+3=6