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mr_godi [17]
3 years ago
15

From 1960 to 2010, a certain money stock measure was growing at the rate of approximately 43e(1/2)x billion dollars per decade,

where x is the number of decades since 1950. Find the total increase in the money stock measure from 1960 to 2010. (Round your answer to the nearest billion dollars.)
Mathematics
1 answer:
natulia [17]3 years ago
6 0

Answer:

1222 billion dollars.

Step-by-step explanation:

To find the total increase from 1960 to 2010, we need to find the growth of each decade and sum them all:

In the period 1960-1970, we have x = 1, and the growth is:

y(1) = 43e(1/2) = 70.895

In the period 1970-1980, we have x = 2, and the growth is:

y(2) = 43e(2/2) = 116.8861

The growth in the following 3 periods are:

y(3) = 43e(3/2) =192.7126

y(4) = 43e(4/2) = 317.7294

y(5) = 43e(5/2) =523.8472

So the total growth in the period 1960 - 2010 is:

Total = y(1) + y(2) + y(3) + y(4) + y(5)

Total = 70.895 + 116.8861+192.726+317.7294+523.8472

Total = 1222.08\ billion\ dollars

Rounding to the nearest billion dollars, we have a total of 1222 billion dollars.

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Genrish500 [490]

Answer:

\pm11,\pm1,\pm\frac{11}{5},\pm\frac{1}{5}

Step-by-step explanation:

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According to the Rational Roots Theorem, the ratio of all factors of the constant term expressed over the factors of the leading coefficient.

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Step-by-step explanation:

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madam [21]

Answer:

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Step-by-step explanation:

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