Hello there.
Question: Find two square numbers that have a sum of 130
Answer: Use trial and error:
It would be 81 + 49 = 130.
Hope This Helps You!
Good Luck Studying ^-^
The formula is a^2+b^2=c^2
C is always the hypotenuse so set it up as 4^2+6^2=(3y-2)^2
Answer:
7.40
Step-by-step explanation:
7.38, we go to the tenths place and the number after then tenths place five or more u raise the score since its more u change hte score of the 3 to 4 and put a zero in the hundredths place
I Think The answer is c I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
Answer:
x=27°
Step-by-step explanation:
we know that
<u><em>The Triangle Exterior Angle Theorem</em></u>, states that: An exterior angle of a triangle is equal to the sum of the opposite interior angles
step 1
Find the measure of angle PLM
we know that
m∠PLM+m∠LPM=m∠PMN ----> by Triangle Exterior Angle Theorem
we have
m∠LPM=x°
m∠PMN=2x+72°
substitute
m∠PLM+x=2x+72°
m∠PLM=2x-x+72°
m∠PLM=x+72°
step 2
Find the measure of angle x
we know that
3x+m∠PLM=180° ----> by supplementary angles (form a linear pair)
we have
m∠PLM=x+72° (see step 1)
substitute
3x+x+72°=180°
4x=180°-72°
4x=108°
x=27°
