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marshall27 [118]
3 years ago
5

Harshdeep was playing basketball with his friends with seconds left before the game ended he attempted a 3 point shot the follow

ing equation models the path of the basketball y=-x^2+4x+5 where x is the elapsed time in seconds.
Pls help, also do i find how long and how high the ball reached or how long it took the basketball to reach the ground. Please answer them as well. Thank you so much.
Mathematics
1 answer:
monitta3 years ago
7 0

Answer:

y = 9 at x = 2 seconds

y = 0 at x = 5 seconds

Step-by-step explanation:

y=-x^2+4x+5

First find the zeros

0 =-x^2+4x+5

0 = -(x^2 -4x -5)

What 2 numbers multiply to -5 and add to -4

-5*1 = -5

-5+1 = -4

0 = -(x-5)(x+1)

x-5 =0    x+1 =0

x=5  x =-1

The vertex is 1/2 way between the two zeros

(5+-1) /2 = 4/2 =2

The vertex is at x=2

The maximum value of y is when x=2

y = -(2)^2 +4(2) +5

y = -4+8+5

y = 9

The ball will hit the ground at x = 5 seconds

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6.0

Step-by-step explanation:

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Answer:

7.07 (3 significant figures)

Step-by-step explanation:

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2 years ago
Please help!!!!<br> I desperately need the correct answer I’ve been trying all day!
zysi [14]

Answer:14708

Step-by-step explanation:Exponential Functions:

y=abxy=ab^x this is not right      not correct

y=ab

x

a=starting value = 13000a=\text{starting value = }13000

a=starting value = 13000

r=rate = 2.5%=0.025r=\text{rate = }2.5\% = 0.025

r=rate = 2.5%=0.025

Exponential Growth:\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.025=1.025b=1+r=1+0.025=1.025

b=1+r=1+0.025=1.025

Write Exponential Function:

y=13000(1.025)xy=13000(1.025)^x

y=13000(1.025)

x

Put it all together

Plug in time for x:\text{Plug in time for x:}

Plug in time for x:

y=13000(1.025)5y=13000(1.025)^{5}

y=13000(1.025)

5

y=14708.30677y= 14708.30677

y=14708.30677

Evaluate

y≈14708y\approx 14708

y≈14708

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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4^{4} is basically 4 × 4 × 4 × 4, which can simplify to 256.

So,  \frac{4^{4}}{4!} = \frac{256}{24}.  \frac{256}{24} can simplify to \frac{32}{3}. Therefore,  \frac{4^{4}}{4!} = \frac{32}{3}.

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