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r-ruslan [8.4K]
2 years ago
12

The point Q lies on the segment PR.

Mathematics
1 answer:
rjkz [21]2 years ago
3 0
Answer: Q. ??
Hope this helps
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A park is 4.6 miles long and 2.7 miles wide. A:what is the total distance around the park? B:if a racecar drove 50 times around
Vlada [557]

Answer:

A) Total distance around the park is 14.6 miles

B) The total distance drove by racer 730 miles

Step-by-step explanation:

Given as :

The length of park = 4.6 miles

The width of park = 2.7 miles

Let the total distance cover around park = Perimeter of park = P miles

So, Perimeter of rectangular park = 2 × Length + 2 × width

or, P = 2 × 4.6 + 2 × 2.7

I.e P = 9.2 + 5.4

Or, perimeter = 14.6 miles

A ) ∴ Total distance around the park = 14.6 miles

B ) The total distance drove by racer = 50 times around the park

  So, The total distance drove by car = 50 × Total distance around the park

∴The total distance drove by car = 50 × 14.6 = 730 miles

Hence A) Total distance around the park is 14.6 miles

          B) The total distance drove by racer 730 miles   answer                                                                              

6 0
3 years ago
Events A1, A2 and A3 form a partiton of the sample space S with probabilities P(A1) = 0.3, P(A2) = 0.5, P(A3) = 0.2.
timurjin [86]

Answer:

Step-by-step explanation:

Given that events A1, A2 and A3 form a partiton of the sample space S with probabilities P(A1) = 0.3, P(A2) = 0.5, P(A3) = 0.2.

i.e. A1, A2, and A3 are mutually exclusive and exhaustive

E is an event such that

P(E|A1) = 0.1, P(E|A2) = 0.6, P(E|A3) = 0.8,

P(E) = P(A_1E)+P(A_2E)+P(A_3E)\\= \Sigma P(E/A_1) P(A_1) \\= 0.1(0.3)+0.5(0.6)+0.8(0.2)\\= 0.03+0.3+0.16\\= 0.49

P(A_1/E) = P(A_1E)/P(E) = \frac{0.3(0.1)}{0.49} \\=0.061224

P(A_2/E) = P(A_2E)/P(E) = \frac{0.5)(0.6)}{0.49} \\=0.61224

P(A_3/E) = P(A_3E)/P(E) = \frac{0.2)(0.8)}{0.49} \\=0.3265

4 0
3 years ago
PLEASE, I AM DESPERATE! CAN ANYONE, HELP ME WITH MY MATH!
Andru [333]
(6,1)&(5,4)
(7,-3)&(4,-8)
(-8,0)&(1,5)
Basically, you are to find the line that passes through 2 points.
Equation: y2-y1=m(x2-x1)
• x1: 6, x2: 5, y1: 1, y2: 4
(4-1)/(5-6)=m
m=3/-1
m=-3
Hence, m= -3x10^0

• x1: 7, x2: 4, y1: -3, y2: -8
(-8--3)/(4-7)=m
m=(-8+3)/-3
m=-5/-3
m=5/3
m=1.66666667
Hence, m=1.6667x10^0

• x1: -8, x2: 1, y1: 0, y2: 5
(5-0)/(1--8)=m
m=5/(1+8)
m=5/9
m=0.55555556
Hence, m=5.56x10^-1

Hope this helps!



5 0
2 years ago
What is the 3rd term when 2y2 + 3y4 – 5y + 6y3 is arranged in descending order?
Hoochie [10]
Arranged in descending order means the terms are arranged in the order of the exponent, from the  largest to the smallest. the exponent is the little number up right to y, 
3y^4+6y^3+2Y^2-5y
so the third term is 2y^2
8 0
3 years ago
don typically works 30 hours per week and earns 13.25 an hour. he is scheduled for a 3% pay increse what will dons new hourly ra
Lana71 [14]
His new hourly pay will be 13.6475

13.25 + 3% = 13.25 + 0.3975 = 13.6475
5 0
3 years ago
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