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cestrela7 [59]
3 years ago
13

Dilate the given points distance from the origin (x,y) (0.8x, 0.8y) . The point (-10,-20) becomes & point (15,25) become

Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

Answer: The point (-10,-20) becomes (-8,-16) & point (15,25) becomes (12,20).

Step-by-step explanation:

When a point (x,y) is dilated by a scale factor k from the origin, then the new points become

(kx,ky).

The given rule of dilation : (x,y) →(0.8x, 0.8y)

The first point is (-10,-20), so its image will be

(-10,-20)\to (0.8\times-10,0.8\times-20)=(-8,-16)

So, the point (-10,-20)  becomes (-8,-16).

The second point is (15,25), so its image will be

(15,25)\to (0.8\times15,0.8\times25)=(12,20)

So, the point (15,25) becomes (12,20).

Hence, the point (-10,-20) becomes (-8,-16) & point (15,25) becomes (12,20).

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N is an integer and - 2<n+3<4, write down the possible values of n from smallest to largest​
Korolek [52]

Answer:

- 4, - 3, - 2, - 1, 0

Step-by-step explanation:

Given

- 2 < n + 3 < 4 ( subtract 3 from each interval )

- 5 < n < 1

This indicates that n ≠ - 5, 1 but all values in between, that is

n = - 4, - 3, - 2, - 1, 0 ← possible values of n

4 0
3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
Read 2 more answers
A contracting company rents a generator for 6 hours and a heavy duty saw for 6 hours total cost of $48 for another job the compa
Wewaii [24]

Answer:

the hourly rates are $8 and $10 respectively

Step-by-step explanation:

Given that

The generator rents for 6 hours and the total cost is $48

And, for another job The generator rents for 4 hours and the total cost is $40

We need to find out the hourly rates

For the first one

= $48 ÷ 6 hours

= $8

For the second one

= $40 ÷ 4 hours

= $10

Hence, the hourly rates are $8 and $10 respectively

6 0
3 years ago
Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uz lz∫uxlx∫uyly????y
SSSSS [86.1K]

Answer:

X from 0 to 21

Y from 0 to 7

Z from 0 to 3

Step-by-step explanation:

Since we are being asked by the integration limits in first octant (positive x, positive y and positive z) we need to know where does the plane intersect this axes. For this we have:

for x=0 and y=0

7z=21

z=3

for x=0 and z=0

3y=21

y=7

for z=0 and y=0

x=21

This means that the integration limits are:

X from 0 to 21

Y from 0 to 7

Z from 0 to 3

8 0
3 years ago
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