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3 years ago

6

the area of the triangle formed by points of intersection of parabola y=a(x-3)(x+2) with the coordinate axes is 10. find a if it

is known that parabola opens upward

1 answer:

Goshia [24]3 years ago

6 0

Answer

1/4 × 6 × (5a) = 12

15a=12

a= 4/5

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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