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uranmaximum [27]
3 years ago
13

Answer number 5 click image.

Mathematics
2 answers:
Brums [2.3K]3 years ago
4 0
55,200× .62 = 34,224 55,200 +34,224 _______ =89,424
natita [175]3 years ago
3 0
That makes 55200*0.62=34224 people.
So 34224 people voted.
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Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...
Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

\displaystle -3x -1, \, 4x +4, \, 11x  + 9 \dots

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

Find the common difference by subtracting the first term from the second:

d = (4x+4) - (-3x - 1)

Distribute:

d = (4x + 4) + (3x + 1)

Combine like terms. Hence:

d = 7x + 5

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}

The 13th term is 81<em>x</em> + 59.

3 0
3 years ago
What are two equivalent forms for 15xyz+10xy+5x
7nadin3 [17]
We can express this number in the standard form, which is simply 15xyz+10xy+5x.  Alternatively, we can factor a 5 or an x out, receiving 5(3xyz+2xy+x) or x(15yz+10y+5).  However, the most effective factorization is to factor out 5x, for a result of 5x(3yz+2y+1).
3 0
3 years ago
Each shape is 1 whole. What fraction greater than 1 names the parts that are shaded?
jeka94
Any number over its self. for example 1,999/1,999
5 0
3 years ago
Find three consecutive numbers whose sum is 171.
-BARSIC- [3]
171/3 is 57. the three consecutive numbers are 56, 57 and 58.

244/4 is 61. the even integers are 58, 60, 62 and 64
5 0
3 years ago
Read 2 more answers
How do I solve this problem?
Paraphin [41]

Answer:

4

Step-by-step explanation:

17-5=12/3=4 so yeah that is all you need to know

4 0
2 years ago
Read 2 more answers
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